The answer is B 3.5(c +a) because u solving for the total money earned and c is is representing for the company
a. Jada got the measurement 16m.
b. The measured depth differ 0.2m from the actual depth.
c. There is a 12.66% error in calculation.
Step-by-step explanation:
Given,
The depth of lake = 15.8 m
a. Jada accurately measured the depth of the lake to the nearest meter. What measurement did Jada get
When a digit after the decimal point is 5 or more than that, the number before decimal is rounded to the next number.
Therefore,
15.8 rounded to nearest number is 16.
The depth of lake measured by Jada = 16 m
Jada got the measurement 16m.
b. By how many meters does the measured depth differ from the actual depth?
Difference = Approx - Exact
Difference = 16 - 15.8 = 0.2m
The measured depth differ 0.2m from the actual depth.
c. Express the measurement error ad a percentage of the actual depth.
Percent error = 
Percent error = 
Percent error = 12.66%
There is a 12.66% error in calculation.
Keywords: percent, error
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Answer:
see below
Step-by-step explanation:
The first part of the function, f(x) = -2x (for x < -1), is only graphed correctly in the first and third graphs.
The second part of the function, f(x) = -1 (for -1 ≤ x < 2) is only graphed correctly in the first graph, which also correctly graphs the third part of the function,
The appropriate choice is the first graph.
recalling that d = rt, distance = rate * time.
we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?

so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.
then Wanda kicks in, rolling like a lightning at 16mph.
let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.
the distance both have travelled is the same "d" miles, reason why they "meet", same distance.
![\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20Hector%26d%2612%26t%2B%5Cfrac%7B3%7D%7B2%7D%5C%5C%5B1em%5D%20Wanda%26d%2616%26t%20%5Cend%7Barray%7D%5Cqquad%20%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Cboxed%7Bd%7D%3D%2812%29%5Cleft%28%20t%2B%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%5C%5C%5B1em%5D%20d%3D%2816%29%28t%29%20%5Cend%7Bcases%7D)
