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Andrei [34K]
2 years ago
13

What is the value of this expression? (−2)^5

Mathematics
1 answer:
dalvyx [7]2 years ago
6 0

Answer:

-32

Step-by-step explanation:

=(-2)^5

=-2*-2*-2*-2*-2-2

-2*-2=4

-2*-2=4

-2

4*4=16

16*-2=-32

Hope this helps :) ❤❤❤

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Please simplify this fraction
saw5 [17]
I hope this helps you

6 0
3 years ago
A theater company charges $3.50 per ticket for people of all age groups. If c represents the total number of children who bought
Anna35 [415]
The answer is B 3.5(c +a)  because u solving for the total money earned and c is is representing for the company
6 0
3 years ago
The depth of a lake is 15.8m
Leya [2.2K]

a. Jada got the measurement 16m.

b. The measured depth differ 0.2m from the actual depth.

c. There is a 12.66% error in calculation.

Step-by-step explanation:

Given,

The depth of lake = 15.8 m

a. Jada accurately measured the depth of the lake to the nearest meter. What measurement did Jada get

When a digit after the decimal point is 5 or more than that, the number before decimal is rounded to the next number.

Therefore,

15.8 rounded to nearest number is 16.

The depth of lake measured by Jada = 16 m

Jada got the measurement 16m.

b. By how many meters does the measured depth differ from the actual depth?

Difference = Approx - Exact

Difference = 16 - 15.8 = 0.2m

The measured depth differ 0.2m from the actual depth.

c. Express the measurement error ad a percentage of the actual depth.

Percent error = \frac{|approx-exact|}{exact}*100

Percent error = \frac{|2|}{15.8}*100 = \frac{200}{15.8}

Percent error = 12.66%

There is a 12.66% error in calculation.

Keywords: percent, error

Learn more about percent at:

  • brainly.com/question/9323337
  • brainly.com/question/9103248

#LearnwithBrainly

4 0
2 years ago
HELP!!! TIMED ASSIGNMENT!!!!! PLEASE HELP
eduard

Answer:

see below

Step-by-step explanation:

The first part of the function, f(x) = -2x (for x < -1), is only graphed correctly in the first and third graphs.

The second part of the function, f(x) = -1 (for -1 ≤ x < 2) is only graphed correctly in the first graph, which also correctly graphs the third part of the function,

The appropriate choice is the first graph.

5 0
3 years ago
I don't know how to do this or what i'm doing plz help
mote1985 [20]

recalling that d = rt, distance = rate * time.


we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

7 0
3 years ago
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