Answer:
The dimensions of the yard are W=20ft and L=40ft.
Step-by-step explanation:
Let be:
W: width of the yard.
L:length.
Now, we can write the equation of that relates length and width:
(Equation #1)
The area of the yard can be expressed as (using equation #1 into #2):
(Equation #2)
Since the Area of the yard is
, then equation #2 turns into:

Now, we rearrange this equation:

We can divide the equation by 5 :

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since
and
. The equation factorised looks like this:

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

Therefore, the dimensions of the yard are W=20ft and L=40ft.
Answer:
x = -5
Step-by-step explanation:
-5(1 - 5x) +5(-8x - 2) = -4x – 8x
First lets simplify each side of the equation.
-5+25x-40x-10 = -4x-8x
Combine like terms
-15x-15=-12x
Add 15x to both sides (addition property of equality)
-15=3x
Divide each side by 3 (division property of equality)
x=-5
The answer is x = -5