Remember that multiples are numbers that can be divided by a number without a remainder so in this case you could add 15 by 15 to find what number in this set is a multiple of 15.
Therefore your answer is "60."
Hope this helps.
Solve the simultaneous equations
1 answer:
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Answer:
1. y=(x+3)^3. Zero: x=-3 multiplicity 3.
2. y=(x-2)^2 (x-1). Zeros: x=2 multiplicity 2; x=1 multiplicity 1.
3. y=(2x+3)(x-1)^2. Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.
Step-by-step explanation:
1. y=(x+3)^3
Zero: x=-3 multiplicity 3.
2. y=(x-2)^2 (x-1)
Zeros: x=2 multiplicity 2; x=1 multiplicity 1
3. y=(2x+3)(x-1)^2
Zeros: x=-3/2 multiplicity 1; x=1 multiplicity 2.