The amount of time needed for a certain machine to process a job is a random variable with mean EXi = 10 minutes and Var(Xi)=2 m inutes2. The times needed for different jobs are independent from each other. Find the probability that the machine processes less than or equal to 40jobs in 7hours.
1 answer:
Answer:
0.98732
Step-by-step explanation:
Given that :
Mean = 10 minutes
Variance = 2 minutes
For less than equal 40 jobs
Mean (m) = 40 * 10 = 400 minutes
Variance = 2 * 40 = 80 minutes
Standard deviation (s) = √variance = √80
Converting hours to minutes
X = 60 * 7 = 420 minutes
P(X≤ 420) :
Z = (x - m) / s
P(X≤ 420) :
Z = (420 - 400) / √80
Z = 20 / √80 = 20 / 8.9442 = 2.236
P(Z ≤ 2.236) = 0.98732
You might be interested in
Answer:
Cant you just type that in the calculator 18 times lol
Step-by-step explanation:
use a calculator
Cows=10 units horses=3 units if 20 cows then 10 units=20 then 1 unit=2 so horses=3 units 1 unit=2 2 times 3=6 6 horses
me neither but this is what i got
3n² p⁴
X + y = 24 x - y = 2 Adding both equations 2x = 26 x = 13 y = 11
Answer: C
Step-by-step explanation:
Place the compass on point and mark an arc above AB that goes through P, and a similar arc below AB.
I just did the CYU and this was correct