All categories

3 years ago

10. The GCD of two numbers is 8 and their

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

3 0

40

Hope this helped :)

You might be interested in

Find the circumference and length of the darkened part of the arc. Leave answer in terms of pi

Allisa [31]

Answer:

Circumference=16pi

Arc Length=8pi

Step-by-step explanation:

Circumference formula=2(pi)(r), or d(pi)

The arc is only half of that in this case, therefore you would only pi(r) or 1/2(d)(pi).

6 0

3 years ago

The sum of 11 and Matt’s savings is 51 use the variable m to represent Matt’s savings

weqwewe [10]

Answer:

40m

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

On a recent road trip, it took Elsa 3.0 h to drive from a suburb of Chicago to a small town outside of Indianapolis. According t

Gemiola [76]

Answer:

Elsa drove 639795 feet.

Step-by-step explanation:

The first step to solve this problem is finding the distance that she drove.

It took 3h for her, at the speed of 65 km/h.

So she traveled 3*65 = 195 km.

How far did Elsa drive in feet

Each km is 3281 feet.

195*3281 = 639795

Elsa drove 639795 feet.

6 0

3 years ago

Find the 4th term of the expansion A B C D

Marysya12 [62]

Answer:

option-A

Step-by-step explanation:

We can use rth term binomial expansion formula

$(x+y)^n$

$T_r=(n,r-1)x^{n-(r-1)}y^{r-1}$

we are given

$(a-\sqrt{2})^8$

we can compare

$x=a,y=-\sqrt{2}$

n=8

r=4

now, we can find 4th term

$T_r=(8,4-1)a^{8-(4-1)}(-\sqrt{2})^{4-1}$

now, we can simplify it

$T_4=\frac{8!}{5!3!}\times -2\sqrt{2}a^5$

$T_4=56\times -2\sqrt{2}a^5$

$T_4=-112\sqrt{2}a^5$

5 0

4 years ago

Read 2 more answers

A man drove 13 miles directly east from his home, made a left turn at an intersection, and then traveled 5 miles due north to hi

Setler79 [48]

$\text{Let the man drove 13 miles directly east from home, A and reach an}\\
\text{intersection point B. Then take a left turn and traveled 5 miles due north}\\
\text{to reach his place of work C.}\\
\\
\text{now if a road was made directly from his home to his place of work,}\\
\text{the distance AC can be found using the Pythagorean theorem. so we have}$

$(AC)^2=(AB)^2+(BC)^2\\
\\
\Rightarrow (AC)^2=(13)^2+(5)^2\\
\\
\Rightarrow (AC)^2=169+25\\
\\
\Rightarrow (AC)^2=194\\
\\
\Rightarrow AC=\sqrt{194}\\
\\
\Rightarrow AC \approx 13.93$

Hence the distance from his home to work place is approximately 13.93 miles

6 0

3 years ago