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Mashutka [201]
3 years ago
6

Subtract. (−9.6x+7)−(7.3x−9) Enter your answer, in simplified form, in the box.Can somebody help me with this equation?

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0
-16.9x + 16 is the correct answer. You have to remove the parentheses, collect the like terms, and then simplify.
Basile [38]3 years ago
5 0

The given expression is (-9.6x+7)-(7.3x-9).

Remove the parentheses, collect the like terms, and then simplify.

(-9.6x+7)-(7.3x-9)=(-9.6x-7.3x)+(7+9)\\ (-9.6x+7)-(7.3x-9)=-16.9x+16.

So the final simplified form is -16.9x+16.

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What is the answer to this
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Answer:

19

Step-by-step explanation:

Add up all the numbers:

3,2,2,2,1,1,1,4,2,1

Then you get 19.

Or you can say it as

3^2 + 2^4 + 1^4 + 4

7 0
3 years ago
How do I get the answer??
Lubov Fominskaja [6]

Answer:

4√10

Step-by-step explanation:

Hello!

Let's first simplify the radical.

We can do this by expanding the radical:

We need to pull out a perfect square factor to expand a radical and simplify it. In 45, we have 9 and 5 multiplied, and 9 is a perfect square.

Let's work with √45:

  • √45 can be written as √9 * √5 (using the rule √ab = √a * √b)
  • √9 simplifies to 3, so it is 3√5

Now we can simplify the operation in the parenthesis by combining like terms:

  • 3√5 + √5
  • √5 + √5 + √5 + √5
  • 4√5

Now using the same rule as above, we can multiply the values:

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Your solution is 4√10

3 0
2 years ago
Which expression is equivalent to ( 4 1/3)^3 ?
shutvik [7]
(13/3)^3 or (13/3)•(13/3)•(13/3)
5 0
3 years ago
What is the nth term rule of the linear sequence below?<br> -9, -5, -1, 3, 7,...
Amiraneli [1.4K]

Answer:

11,15,19,23,27,31,35,39,43,47,51,....

6 0
3 years ago
given a geomatric progression 2,6,18,54... find the smallest value of n such that the nth term is greater than 100000​
stiks02 [169]

Answer:

hello,

Step-by-step explanation:

u_1=2=2*3^0\\u_2=6=2*3^1\\u_3=18=2*3^2\\u_4=54=2*3^3\\\\....\\u_n=2*3^{n-1}\geq 100000\\\\3^{n-1}\geq 50000\\\\(n-1)*ln(3)\geq ln(50000)\\\\n-1\geq 9,848586...\\\\n\geq 10.848586....\\\\\boxed{n=11}\\

6 0
2 years ago
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