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Umnica [9.8K]
2 years ago
7

HELP FAST!!

Mathematics
1 answer:
katrin2010 [14]2 years ago
3 0
I got b I think that’s the answer
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A company plans to enclose three parallel rectangular areas for sorting returned goods. The three areas are within one large rec
Svetlanka [38]

Answer:

The largest total area that can be enclosed will be a square of length 272 yards.

Step-by-step explanation:

First we get the perimeter of the large rectangular enclosure.

Perimeter of a rectangle =2(l + w)

Perimeter of the large rectangular enclosure= 1088 yard

Therefore:

2(L+W)=1088

The region inside the fence is the area

Area: A = LW

We need to solve the perimeter formula for either the length or width.

2L+ 2W= 1088 yd

2W= 1088– 2L

W = \frac{1088-2L}{2}

W = 544–L

Now substitute W = 544–L into the area formula

A = LW

A = L(544 – L)

A = 544L–L²

Since A is a quadratic expression, we re-write the expression with the exponents in descending order.

A = –L²+544L

Next, we look for the value of the x coordinate

L= -\frac{b}{2a}

L= -\frac{544}{2X-1}

L=272 yards

Plugging L=272 yards into the calculation for area:

A = –L²+544L

A(272)=-272²+544(272)

=73984 square yards

Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:

W = 544 – L

= 544 – 272

= 272 yards

7 0
3 years ago
Help please .!!!!!!!!?
sammy [17]
15x over 2 dont know how to do it on computer

4 0
3 years ago
Read 2 more answers
Now suppose instead that Jane withdraws $500 from her checking account and uses $300 of this money to pay her federal income tax
zysi [14]

Answer:

Step-by-step explanation:

a. Money held by individuals in savings accounts is part of the M2 money supply, but not part ofthe M1 money supply. Therefore, when Jane withdraws $500 cash from her savings account,the M1 money supply increases by $500. However, the M2 money supply does not changebecause the M1 money supply is included as part of the M2 money supply.b. Money held by banks and governments is not included as part of the money supply. Therefore,when Jane uses $300 to pay her income tax to the U.S. Treasury, that total of $300 is taken out ofboth the M1 and M2 money supplies. When Jane deposits the remaining cash ($80) into hersavings account, the M1 money supply is reduced by that amount, but it does not affect the M2money supply. Therefore, Jane's actions cause the M2 money supply to change by ­$300 (theamount used to pay her taxes) and the M1 money supply to change by ­$380 (the amount used topay her taxes plus the amount that was deposited into her savings account). Note that it does notmatter that Jane no longer has the $120 she used to pay for the gold clubs, as the funds remainsin someone else's checking account. So this amount is neither removed from the M1 moneysupply nor the M2 money supply.NumericResponseDifficulty: 03 HardLearning Objective: 14­02 List anddescribe the components of the U.S.money supply.5000­380­300References

5 0
3 years ago
Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t
Amanda [17]

Answer:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

df = n-1= 22-1=21

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

\bar X=33.9 represent the sample mean

s=4.1 represent the sample standard deviation

n=22 sample size  

\mu_o =26 represent the value that we want to test

\alpha=0.025 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:  

Null hypothesis:\mu \geq 36  

Alternative hypothesis:\mu < 36  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replacing we got:

t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402    

Now we can calculate the critical value but first we need to find the degreed of freedom:

df = n-1= 22-1=21

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

t_{\alpha/2}= -2.08

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

3 0
3 years ago
What is the reciprocal of 3 and 1/5
Vaselesa [24]
1/3 and 5 because 3/1 is three and 1/3 is the opposite while 1/5 is 5/1 which is 5.
4 0
3 years ago
Read 2 more answers
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