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Sphinxa [80]
3 years ago
11

Find the slant height of a square pyramid with base edges of 12 cm and an altitude of 8 cm?

Mathematics
2 answers:
liberstina [14]3 years ago
8 0
To find the slant height we must take apart the pyramid first. Let us cut it in half. There we can easily see that the slant height is really just the hypotenuse of the triangle formed by half the base and the altitude.

Half the base length would be 6 cm.

Using the Pythagorean therom:

a² + b² = c²
6² + 8² = c²
36 + 64 = c²
100 = c²
c = 10

The slant height should be 10 cm. Hope this helps!
Mashcka [7]3 years ago
4 0
The answer is 10 centimeters.
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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B29-12%5Csqrt%7B5%7D" id="TexFormula1" title="\sqrt{29-12\sqrt{5}" alt="\sqrt{29-12\s
SSSSS [86.1K]

\sqrt{29 \:  -  \: 12 \sqrt{5} }

  • Factor the indicated expression:

\sqrt{(3 \:  -  \: 2 \sqrt{5}) ^{2}  }

  • Simplified the index the root and also the exponent using the number 2.

\boxed{ \bold{2 \sqrt{5}  \:  -  \: 3}}

<h3><em><u>MissSpanish</u></em> </h3>
6 0
2 years ago
Read 2 more answers
Quadrilateral ABCD is dilated by a scale factor of 1 over 2 centered around (2, 2). Which statement is true about the dilation?
Musya8 [376]

Answer:

Option (1)

1) Segment B'D' will run through (2, 2) and will be shorter than segment BD.

Step-by-step explanation:

The rest of the question is the attached figure (1).

The statement options are:

1) Segment B'D' will run through (2, 2) and will be shorter than segment BD.

2) Segment B'D' will run through (2, 2) and will be longer than segment BD.

3) Segment B'D' will parallel to segment BD and will be shorter than segment BD.

4) Segment B'D' will be parallel to segment BD and will be longer than segment BD.

==============================================================

See the attched figure (2), which represents Quadrilateral ABCD and the image A'B'C'D'

As shown:

The quadrilateral ABCD with vertices A(1,2), B(2,3), C(4,2) and D(2,1).

Quadrilateral ABCD is dilated by a scale factor of 1 over 2 centered around (2, 2).

So,

The quadrilateral A'B'C'D' will be with vertices:

A'= (1.5,2), B'= (2,2.5), C'= (3,2), D'= (2,1.5)

Comparing the options with the figure (2):

So, the answer is option (1)

1) Segment B'D' will run through (2, 2) and will be shorter than segment BD.

6 0
3 years ago
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