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3 years ago

How do i quit branily

Mathematics

2 answers:

fiasKO [112]3 years ago

7 0

Answer:

Log out, delete your account, or make bad questions to get banned.

Step-by-step explanation:

Andre45 [30]3 years ago

5 0

Answer:

look it up

Step-by-step explanation:

You might be interested in

Write the expression for when you translate the graph of y = | 1/2 x−2 |+3 a) one unit up, b) one unit down, c) one unit to the

alukav5142 [94]

Answer:

a) y = |x/2 -2| +4

b) y = |x/2 -2| +2

c) y = |(x+1)/2 -2| +3

d) y = |(x-1)/2 -2| +3

Step-by-step explanation:

To translate the function f(x) by (h, k) in the (right, up) direction, you transform it to ...

g(x) = f(x -h) +k

a) one unit up

Add 1 to the function value.

$y=\left|\dfrac{x}{2}-2\right|+3+1\\\\\boxed{y=\left|\dfrac{x}{2}-2\right|+4}$

b) one unit down

Subtract 1 from the function value.

$y=\left|\dfrac{x}{2}-2\right|+3-1\\\\\boxed{y=\left|\dfrac{x}{2}-2\right|+2}$

c) one unit left

Replace x with x-(-1).

$y=\left|\dfrac{x-(-1)}{2}-2\right|+3\\\\\boxed{y=\left|\dfrac{x+1}{2}-2\right|+3}$

d) one unit right

Replace x with x-1.

$\boxed{y=\left|\dfrac{x-1}{2}-2\right|+3}$

7 0

3 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

4 years ago

Write an expression in expanded form and an expression in factored form for the diagram.

olga2289 [7]

Step-by-step explanation:

You put them together to form a bigger number then break it down. sorry if it doesn't make sense.

Btw do you form the number if so I'll help just give the number and I'll break it down for you. :)

6 0

4 years ago

Read 2 more answers

Find the arc length of the following problem:

Harrizon [31]

Answer:

$61.261 {ft}^{2}$

Step-by-step explanation:

$\frac{270}{360} \times 2\pi \: r \\ \frac{270}{360} \times 2 \times \pi \times 13 \\ = 61.261 {ft}^{2}$

<h3>Can I have the brainliest please?</h3>

5 0

3 years ago

Read 2 more answers

3. Last year, the numbers of calculators produced per day at a certain factory were normally distributed with a mean of 560 calc

Mademuasel [1]

Answer:

3. Last year, the numbers of calculators produced per day at a certain factory were normally distributed with a mean of 560 calculators and a standard deviation of 12 calculators.(C)

Step-by-step explanation:

please click the heart and rate excellent and brainleist to ❤☺️☻♨️☻☺️❤

8 0

3 years ago