Sqrt 18, 41/9, 4.556, 4.56, then lastly 4 5/8. Hope this helps!
So, you would 13 + 9 = which is 22 feet and since the angle is 50 degrees, you would multiply 22 x tan(50) to find the height of the streetlamp:22 x tan(50) = 26.21. So, the streetlamp is about 26 feet tall!Hope this helps!
Answer:
m∠APC = 30°
Step-by-step explanation:
To solve for the above question, we would be making use of circle theorems
Looking at the circle, we can see that
m∠APC is an Angle outside the circle
m∠AOC is a smaller arc in the circle.
Therefore, Circle Theorem states that for a circle with two tangents,
The Angle outside the circle + The smaller arc = 180°
Hence,
m∠AOC + m∠APC = 180°
m∠APC = 180° - m∠AOC
m∠APC = 180° - 150°
m∠APC = 30°
The initial dimenssions of the park lot are:
length: 140 ft
width: 90 ft
initial area: 140 * 90 = 12,600 ft^2
Area increased 29% = 12,600 * 1.29 = 16,254 ft^2
width of the strips: x
New length: 140 + x
New width: 90 + x
New area: (140+x)(90+x) = 16,254
Solution of the equation:
12600 + 230x + x^2 = 16254
=> x^2 + 230x - 3654 = 0
Use the quadratic formula.
x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =
x = 14.92
The other solution is negative so it is discarded.
Answer: 15 ft
