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2 years ago

HELP ME WITH ANGLES PLEASE>

Mathematics

2 answers:

Sindrei [870]2 years ago

8 0

Answer:

x = 33

Step-by-step explanation:

Pls brainliest I knew it because of K12

Iteru [2.4K]2 years ago

4 0

X = 33

hope i helped <3

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The length of the transverse axis is 6 and the length of the red line segment is 14 how long is the blue line segment

lapo4ka [179]

Answer:

Step-by-step explanation:

it is not longer then the red line or equal but is bigger then the green line so there is how i got 8

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3 years ago

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A rectangular prism is 24mm in height 13mm width and 29mm in lenght what is the surface area?

aev [14]

The surface area of a rectangular prism is:

A=2(LW+HW+LH) in this case:

A=2(24*13+24*29+13*29)

A=2(1385)

A=2770 mm^2

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2 years ago

There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro

elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that $\mu = 20.1, \sigma = 5.1$ .

You scored 24 on Exam A. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{24 - 20.1}{5.1}$

$Z = 0.76$

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that $\mu = 1031, \sigma = 215$ .

You scored 1167 on Exam B, s:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1167 - 1031}{215}$

$Z = 0.632$

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0

3 years ago

What are the expressions?

Romashka [77]

<h2>Explanation:</h2>

Here we need to solve some expressions. Remember the following rules:

$(+)(+)=+ \\ \\ (-)(-)=+ \\ \\ (+)(-)=- \\ \\ (-)(+)=-$

Then, from the left side:

$5-2\cdot 7=5-14=\boxed{-9} \\ \\ 5-2\cdot 4=5-8=\boxed{-3} \\ \\ 5-2\cdot 0=5-0=\boxed{5} \\ \\ 5-2\cdot -3=5+6=\boxed{11} \\ \\ 5-2\cdot 10=5-20=\boxed{-15} \\ \\ 5-2\cdot -8=5+16=\boxed{21} \\ \\$

from the right side:

$-(-4)+3=4+3=\boxed{7} \\ \\ -(6)+3=-6+3=\boxed{-3} \\ \\ -(-8)+3=8+3=\boxed{11} \\ \\ -(-5)+3=5+3=\boxed{8} \\ \\ -(2)+3=-2+3=\boxed{1} \\ \\ -(15)+3=-15+3=\boxed{-12} \\ \\ -(-6)+3=6+3=\boxed{9}$

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3 years ago

A right-angled triangle has one side of length 1.5 cm. Its hypotenuse is 6 cm. How long is its other side?

irga5000 [103]

Answer:

Step-by-step explanation:

pythagorean theorem. a^2+b^2=c^2

1.5^2+b^2=6^2

2.25+b^2=12

12-2.25=b^2

b^2=9.75

take the square root

b=3.12

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3 years ago

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