<span>x^2+16x+24: Think: What are the integer factors of 24? I'd list 1, 2, 3, 4, 6, 8, 12 and 24. Next: Look for a pair of factors from that list that:
(1)ADD up to 16 AND (2) whose product is 24. Unfortunately there seems to be no such pair from the above list.
So: Use the quadratic formula to find the roots of </span>x^2+16x+24:
-16 plus or minus sqrt[ 256-4(1)(24) ]
x = --------------------------------------------------
2
-16 plus or minus sqrt(160) -16 plus or minus 4 sqrt(10)
= --------------------------------------- = ----------------------------------------
2 2
2(-8 plus or minus 2 sqrt(10) )
= ------------------------------------------- = -8 plus or minus 2sqrt(10)
2
If c is a root, (x-c) is a factor. Thus, if -8 plus 2sqrt(10) is a root,
(x+8-2sqrt(10) is a factor. Can you find the other factor?
x^2-10a+25 is much easier to factor. The sqrt of 25 is 5, so try x= -5 as a root. Dividing x-5 into <span>x^2-10a+25, we get x-5. Therefore, the factors are
(x-5) and (x-5).</span>
Answer:
Step-by-step explanation:
hello :
A) X=In(125)
H= -32t + 541 The final solution for h is <<<<
Answer:
<u>The correct answer is A. 1 +/- i √31/2</u>
Step-by-step explanation:
Let's use the quadratic formula to solve the equation:
x² - x + 8 = 0
Let's recall that the quadratic equation is:
x = (-b +/- √(b² - 4ac))/2a
In the equation, a = 1, b = -1, c = 8.
Replacing with the real values, we have:
x = (-b +/- √(b² - 4ac))/2a
x = (- (-1) +/- √(-1² - 4 (-1) (8)))/2(1)
x = (1 +/- √( 1 - 32)/2
x = (1 +/- √( - 31)/2
x = (1 +/- √( -1 * 31)/2
Let's recall that √ -1 = i
x = 1 +/- i √ 31/2
<u>The correct answer is A. 1 +/- i √31/2</u>
