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bazaltina [42]
4 years ago
7

Determine is an outlier is present in the given data set: 43, 69, 78, 88, 54, 73, 54, 59,70

Mathematics
1 answer:
kodGreya [7K]4 years ago
6 0

Answer:

43

Step-by-step explanation:

43 is the most the lowest number while the others are around the same range

Hope this helps! Pls mark brainliest!

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17<br> Σ (15 – 9n)<br> η = 4
Rama09 [41]

Answer:

  -1113

Step-by-step explanation:

You apparently want the sum of the 14-term arithmetic sequence ...

  -21, -30, -39, ..., -138

The average term is ...

  (-21 -138)/2 = -79.5

so the sum of the 14 terms is ...

  (14)(-79.5) = -1113

6 0
4 years ago
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Find sec Θ if the terminal side of Θ in standard position contains the point (4, -3)
CaHeK987 [17]
If we plot that point we find ourselves in QIV.  The distance along the x axis is 4, and the distance down from that point is -3.  If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle.  We need its measure.  Using Pythagorean's theorem, 4^2+-3^2=c^2 and 16+9=c^2.  We see that c = 5.  We need now to find the secant of that right triangle.  Secant if the co-identity of cosine which is side adjacent over hypotenuse.  That means that secant is the hypotenuse over the side adjacent.  So our secant theta = 5/4
7 0
3 years ago
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What is y=mx+b and how do I find it
MatroZZZ [7]
This is the slope formula.
7 0
4 years ago
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-18 is greater than or equal to -6c solve for c
kherson [118]
-18>=-6c
Divide both sides by -6 to get c by itself on one side. Also, flip the greater than sign to a less than or equal to sign because you divided by a negative number.
Final Answer: 3<= c
4 0
3 years ago
If <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%20%2B%20ib%7D%7Bc%20%2B%20id%7D%20" id="TexFormula1" title=" \frac{a + i
Simora [160]

Rewrite the given number as

\dfrac{a+ib}{c+id}=\dfrac{(a+ib)(c-id)}{(c+id)(c-id)}=\dfrac{ac+bd+i(bc-ad)}{c^2+d^2}

If it's purely real, then the complex part should be 0, so that

\dfrac{bc-ad}{c^2+d^2}=0\implies bc-ad=0\implies\boxed{ad-bc}

as required.

7 0
3 years ago
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