A. 135 B. 45 C. 45 I believe or A and B are switched... so ( A. 45, B. 135)
<h2>
Answer:</h2>
a)
The probability that both televisions work is: 0.42
b)
The probability at least one of the two televisions does not work is:
0.5833
<h2>
Step-by-step explanation:</h2>
There are a total of 9 televisions.
It is given that:
Three of the televisions are defective.
This means that the number of televisions which are non-defective are:
9-3=6
a)
The probability that both televisions work is calculated by:

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.
and the total outcome is the selection of 2 televisions from a total of 9 televisions)
Hence, we get:

b)
The probability at least one of the two televisions does not work:
Is equal to the probability that one does not work+probability both do not work.
Probability one does not work is calculated by:

and the probability both do not work is:

Hence, Probability that atleast does not work is:
0.5+0.0833=0.5833
Answer:
B. 30x
D. x(45-15)
Step-by-step explanation:
The distributive property lets you factor out the common factor of x. The sum of coefficients can be simplified to a single coefficient.
45x -15x = x(45 -15) = 30x
Answer:
20x+68
Step-by-step explanation:
<span><span>
q−9</span>=12
</span>Step 1: Add 9 to both sides.
<span><span><span>q−9</span>+9</span>=<span>12+9
</span></span><span>q=21
</span>Answer:
<span>q=21</span>