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GarryVolchara [31]
3 years ago
12

I need help fast pleasee

Mathematics
2 answers:
algol [13]3 years ago
5 0

Answer:

it is the first one on the left with the triangles

Step-by-step explanation:

They both have the same angles and the side length ratio is the same, All one have to do to get one from the other is multiply the side lengths of the smaller triangle by 2. or divide the bigger one by 2.

VashaNatasha [74]3 years ago
4 0
Hey can you please help me with a math question I posted it. Thank you
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Plz answer ASAP x=? thx
mrs_skeptik [129]
X is 10

I have shown the calculation in the attachment.

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3 years ago
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On Monday, the high was 60oF. On Tuesday, the high was 10% more than Monday. Then on Wednesday, the temperature decrease by 8%.
Arada [10]

Answer:

60.72

Step-by-step explanation:

Monday: 60 degrees

Tuesday: temperature increases by 10 percent

60 + 10% of 60

60 + .10*60 = 70 +6 = 66

Wednesday: temperature decreases by 8 percent

66 - 8%of 66

66 - .08*66 = 66 -5.28=60.72

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3 years ago
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Evalute costheta if sintheta = (sqrt5)/3
torisob [31]

Answer:

\large\boxed{\cos\theta=\pm\dfrac{2}{3}}

Step-by-step explanation:

Use \sin^2x+\cos^2x=1.

We have

\sin\theta=\dfrac{\sqrt5}{3}

Substitute:

\left(\dfrac{\sqrt5}{3}\right)^2+\cos^2\theta=1\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(\sqrt5)^2}{3^2}+\cos^2\theta=1\qquad\text{use}\ (\sqrt{a})^2=a\\\\\dfrac{5}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{5}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{9}{9}-\dfrac{5}{9}\\\\\cos^2\theta=\dfrac{4}{9}\to \cos\theta=\pm\sqrt{\dfrac{4}{9}}\\\\\cos\theta=\pm\dfrac{\sqrt4}{\sqrt9}\\\\\cos\theta=\pm\dfrac{2}{3}

3 0
3 years ago
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Find (f ° g)(0). *
atroni [7]

Answer:

B

Step-by-step explanation:

Remark

I have to represent f(x) as plus +f(x)

I like to show this situation as +f(g(x)) which I think is much clearer.

+f(x) = 5x - 4    

Solution

+f(g(x)) = 5(g(x)) - 4  What has happened is that wherever you see an x on the right you put in g(x).

Now on the right, you put whatever g(x) is equal  to.

+f(g(x)) = 5(x^2 - 1)  - 4    

Remove the brackets.

+f(g(x)) = 5x^2 - 5 - 4

And make x = 0

+f(g(0)) = 5*0 - 5 - 4

+f(g(0)) = - 9

8 0
2 years ago
Divide using a common factor of 3 to find an equivalent fraction for
fgiga [73]
3/12 = (3÷3)/(12÷3) = 1/4
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2 years ago
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