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Alekssandra [29.7K]
3 years ago
15

A cross country skier reaches the 3km mark of a race in 15 min and 12 km mark 45 min later. Assuming a contrast rate find the sp

eed of the skier
Mathematics
1 answer:
melomori [17]3 years ago
4 0
To find the speed you must write S= d/t so for the first one we will chang 15 m to b so it is = 0.25h so s=3/0.25h = 12km/h an why secand is 45 m to h = 0.75h so S=d/t S =12/0.75 =16 km/h the to find the totel speed we should + the speed together so 12 + 16 = 28 km/h
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A prism is dilated by a factor of 1.5. How many times larger is the volume of the resulting prism than the volume of the origina
Temka [501]

Answer:

The answer is 3.375

r = (1.5)^3

= 3.375

4 0
3 years ago
Read 2 more answers
Which situation will have the greatest number of permutations?
Anton [14]

Answer:

Option C will have greatest number of permutations.

Step-by-step explanation:

A.

The number of license plates with 4 letters followed by 3 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

23 letter options for 4th letter.

So total options for 4 letters 26*25*24*23 = 358800

Now, 3 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

9 number options for 2nd number

8 number options for 3rd number

Total options for 3 numbers= 10*9*8 = 720

total options for 4 letters and 3 numbers will be: 358800 * 720 = 258,336,000

B.

The number of license plates with 3 letters followed by 4 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

So total options for 3 letters= 26*25*24 = 15600

Now, 4 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

9 number options for 2nd number

8 number options for 3rd number

7 number options for 4th number

Total options for 4 numbers = 10*9*8*7 = 5040

total options for 4 letters and 3 numbers will be: 15600 * 5040 = 78,624,000

C. The number of license plates with 4 letters followed by 3 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 4 letters and 10 options for each 3 numbers

26*26*26*26 *10*10*10 = 456,976 * 10,00 = 456,976,000

total options for 4 letters and 3 numbers will be: 456,976,000

D.

The number of license plates with 3 letters followed by 4 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 3 letters and 10 options for each 4 numbers

26*26*26 *10*10*10*10 = 17,576 * 10,000 = 175,760,000

total options for 3 letters and 4 numbers will be: 175,760,000

So, Option C will have greatest number of permutations.

7 0
3 years ago
Trying to help my kid​
nikklg [1K]

Answer:

2/(3a^(1/3))

Step-by-step explanation:

The derivative of g(x) = 2/(3x^(1/3))

you get this by bringing the exponent of g(x) down and the new exponent is (2/3) - 1 .

Then replace x with a

8 0
3 years ago
SOMEONE PLZZZZ HELP ME! ITS WORTH 12 POINTS AND BRAINLEST! What is the area of one of the triangular faces
dmitriy555 [2]

Answer:

The answer is

Step-by-step explanation:

3 0
3 years ago
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The probability of passing the math class of Professor Goodrum is 59%, the probability of passing Professor Cruise's physics
liq [111]

Answer:

  51%

Step-by-step explanation:

Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.

<h3>Probability relations</h3>

We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).

The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:

  42% +9% = 51%

The probability of passing one or the other is 51%.

__

<em>Additional comment</em>

We can also get there using the relation ...

  P(A+B) = P(A) +P(B) -P(AB)

The union of A and B also includes their overlap:

  P(A+B) = P(AB') +P(A'B) +P(AB)

In other words, the probability of interest is ...

  P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)

  P(AB') +P(A'B) = 51%

6 0
1 year ago
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