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Alekssandra [29.7K]
3 years ago
15

A cross country skier reaches the 3km mark of a race in 15 min and 12 km mark 45 min later. Assuming a contrast rate find the sp

eed of the skier
Mathematics
1 answer:
melomori [17]3 years ago
4 0
To find the speed you must write S= d/t so for the first one we will chang 15 m to b so it is = 0.25h so s=3/0.25h = 12km/h an why secand is 45 m to h = 0.75h so S=d/t S =12/0.75 =16 km/h the to find the totel speed we should + the speed together so 12 + 16 = 28 km/h
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Phil has two rectangular prisms. The height of the second prism is 1/2 times the height of the first prism. The lengths and widt
Vesnalui [34]

The volume of the second prism is also ten times the volume of the first prism.

Let's assume that both prisms have:

width = 3 units

height = 4 units

Prism 1 length = 5 units

Prism 2 length = 50 units

Let's solve their respective volumes to compare...

Volume of prism 1 = length * width * height

                             = 5 * 3 * 4

                             = 60 units ^3

Volume of prism 2 = 50 * 3 * 4

                             = 600 units ^3

Prism 2/ prism 1 = 10

That means prism 2 is ten times the volume of prism 1.

6 0
3 years ago
Sum of two numbers is 84. If one of the numbers exceeds the other by 12, the numbers are
djverab [1.8K]

Answer:

54 and 30

Step-by-step explanation:

84÷2=42-12=30

42+12=54

5 0
3 years ago
Please help! Best answer will get brainliest!
marysya [2.9K]
The answer is -110.
8 0
3 years ago
Find the right quotient. 36m 5 n 5 ÷ (12m 3)
polet [3.4K]
ANSWER

The right quotient is

3  {m}^{2} {n}^{5}

EXPLANATION


The given expression is :

\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  \frac{36}{12}  \times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3\times  \frac{ {m}^{5} }{ {m}^{3}} \times  {n}^{5}


Recall that,


\frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n}
We apply this property to obtain;



\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3 \times   {m}^{5 - 3}  \times  {n}^{5}


\frac{36 {m}^{5} {n}^{5}  }{12 {m}^{3} }  =  3  {m}^{2} {n}^{5}

5 0
3 years ago
Read 2 more answers
Martin ordered a pizza with a 12-inch diameter. Ricky ordered a pizza with a 16-inch diameter. What is the approximate differenc
adell [148]

Answer:

88 in²

Step-by-step explanation:

The shape of a pizza = Circular

Area of a circle = πr²

For Martin

Martin ordered a pizza with a 12-inch diameter.

Radius = Diameter/2 = 12 inch/2 = 6 inch

Area of Martin's pizza = π × 6²

= 113.09733553 in²

≈ 113.1 in²

For Ricky

Ricky ordered a pizza with a 16-inch diameter.

Radius = Diameter/2 = 16 inch/2 = 8 inch

Area of Martin's pizza = π × 8²

= 201.06192983in²

= 201.1in²

The approximate difference in area of the two pizzas in square inches is calculated as:

201.1 in² - 113.1 in²

= 88 in²

8 0
3 years ago
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