What is 0.125 written as a fraction in simplest form?

Shelly is a baker she is using batter to make pancakes. Which is the dependent variable the batter or the pancakes. Which is the

Nesterboy [21]

Answer:

The Pancakes are actually dependent while the Batter is Independent because your are changing the batter. Think of I change in an Independent variable. You cant really change the outcome which is the dependent.

Step-by-step explanation:

4 0

3 years ago

Translate "The product of the cube root of 5 and X^ prime prime into an algebraic expression

svp [43]

Answer:

Le produit de la racine cubique de 5 et de X ^ prime prime en une expression algébrique: french, youre welcome.

Step-by-step explanation:

5 0

3 years ago

HELP! I don't understand so please give a detailed explanation.

likoan [24]

From the picture, we can see that ΔLSP and ΔLRN are similar, so corresponding sides are proportionate:

LN : LP = 28:12 = 7:3

Therefore, the LRN sides is 7/3 of the corresponding side of LSP.

Then, it states that the area of LSP = 50, and area of a triangle is (1/2)bh, so we set up the equation

Area of LSP = (1/2)bh = 50 ← Remember how the corresponding sides are 7/3 of LSP? Therefore, the area of LRN:

LRN = (1/2)(7b/3)(7h/3) ← Take out the 7/3 and multiply them together

= (49/9)(1/2)bh ← From LSP, we know that (1/2)bh = 50, so plug that in

= (49/9)*50 ≈ 272.222 units ²

6 0

3 years ago

Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq

AnnyKZ [126]

Answer:

$(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Step-by-step explanation:

Step(i):-

Given that the function

f(x) = $e^{4x} \sqrt{1+e^{2x} }$

Now integrating on both sides, we get

$\int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx$

= $\int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx$

Step(ii):-

Let $1 + e^{2x} = t$

$e^{2x} = t -1$

$2e^{2x}dx = d t$

$e^{2x}dx = \frac{1}{2} d t$

= $\int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx$

= $\int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }$

= $\frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }$

= $\frac{1}{2} \int\limits {(t^{\frac{1}{2} } t^{1} +t^{\frac{1}{2} } ) } \, dx$

$= \frac{1}{2} \int\limits {(t^{\frac{3}{2} } +t^{\frac{1}{2} } ) } \, dx$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C$

= $\frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C$

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Final answer:-

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

3 0

3 years ago

Find the greatest common factor of 15x2y3 and -20x3yz.

siniylev [52]

Answer:

5xy

Step-by-step explanation:

4 0

3 years ago

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