Given:
A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind.
Pilot's speed in still air is 315 miles per hour.
To find:
The speed of the wind.
Solution:
Let the speed of wind be x miles per hour.
Speed with wind = 315+x miles per hour
Speed against wind = 315-x miles per hour
We know that,
According to the question,
Divide both sides by 90.
By cross multiplication, we get
Divide both sides by 9.
Therefore, the speed of wind is 35 miles per hour.
Answer with explanation:
<u>Part A: </u>
One solution.
The number of points of intersection represents the number of solutions. Since the two lines only intersect at one point, there is only one solution.
<u>Part B:</u>
(3, 4)
The point(s) of intersection marks the solution(s) to the lines. Since lines A and B intersect at the point (3, 4), the solution to the equation of their lines is (3, 4), or , as coordinates are written as (x, y).
Answer:
Step-by-step explanation:
Assuming this problem :"Only 30% of the students in a certain liberal arts college are males. If two students from this college are selected at random, what is the probability that they are both males?"
Previous concepts
An independent event is an "event that has no connection to another event's chances of happening ". For this case we can assume that if one person is male and if we select another one the probability that this one would be male or female is totally indepedent from the first selection.
When we have two independent events let's say A and B and we want to find the probability that both events occurs at the same time we can use the following formula:
Solution to the problem
We can define some notation:
first person selected is a male
second person selected is male
On this case we want the probability that both would be males. And we can express this like this on math terms:
For this case we can assume that the two events are independent. And in order to find the probability for two events independents events we just need to multiply the probabilities of each one like this: