Answer:
6-7-8-9-10-11-12-13-14-15 etc...
Step-by-step explanation:
any number that is equal to 6 or greater than 6 is a possible value for x.
200 times. Because 1000 divided of 5 is 200. You could divide it using the algorithm.
Evaluate the trigonometric expression using sum and difference formulas.
A) x² + y² = 327
B) x * y = 101
Solving equation B for y²
B) y² = 10,201 / x²
Substituting this into equation A)
x² + 10,201 / x² = 327
x^4 + 10,201 = 327x²
x^4 -327x² + 10,201 = 0
Using the quartic equation calculator: http://www.1728.org/quartic.htm
x1 = 17.090169943749476
x2 = 5.909830056250525
x1 * x2 = 101
x1 + x2 = 23
