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Snowcat [4.5K]
3 years ago
13

Plz Help With This Math Brainliest First Person

Mathematics
1 answer:
In-s [12.5K]3 years ago
4 0

Answer:

∠L = 54°

Step-by-step explanation:

5x + 2x + 3x = 180 (all angles in a triangle add up to 180)

10x = 180

x = 18°

∠L = 3x

sub x = 18

3(18) = 54

∠L = 54°

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Emma is playing miniature golf. Her ball is 2 feet of the right-wall. The hole is 4 feet to the left of the wall. The distance a
GalinKa [24]

Answer:

She should aim 6 feet down the wall

Explanation:

The diagram attached sketches the situtation.

Since the angle with which the ball hits the wall is the same with which it bounces, angle β is the same for the two shown triangles.

Then, since both are right triangles, then all the angles are congruent and the triangles are similar. Hence, you can equal the ratios of the sides, to make an equation:

x/4 = y/2 ⇒ x = 2y

You have other equation:

x+ y = 18

Substitute

2y + y = 18

3y = 18

y = 18/3

y = 6 ← this is the distance down the wall where the ball should hit

x = 2(6) = 12

Then, she should aim 6 feet down the wall.

4 0
2 years ago
What is 3x-4=18+5x ?
My name is Ann [436]
3x - 4 = 18+5x
-3x             -3x

-4-18 = 18 + 2x
       -18

-22 = 2x

2x/2 = -22/2

x= -22/2

x= -11

Final answer: x = -11
7 0
3 years ago
1. The figure shows the regular triangular pyramid SABC. The base of the pyramid has an edge AB = 6 cm and the side wall has an
Musya8 [376]

Given:

• AB = 6 cm

,

• SM = √15 cm

Let's solve for the following:

• 1) the base elevation AM.

Given that we have a regular triangular pyramid, the length of the three bases are equal.

AB = BC = AC

BM = BC/2 = 6/2 = 3 cm

To solve for AM, which is the height of the base, apply Pythagorean Theorem:

\begin{gathered} AM=\sqrt{AB^2-BM^2} \\  \\ AM=\sqrt{6^2-3^2} \\  \\ AM=\sqrt{36-9} \\  \\ AM=\sqrt{27} \\  \\ AM=5.2\text{ cm} \end{gathered}

The base elevation of the pyramid is 5.2 cm.

• (2)., The elevation SO.

To find the elevation of the pyramid, apply Pythagorean Theorem:

SO=\sqrt{SM^2-MO^2}

Where:

SM = √15 cm

MO = AM/2 = 5.2/2 = 2.6 cm

Thus, we have:

\begin{gathered} SO=\sqrt{(\sqrt{15})^2-2.6^2} \\  \\ SO=\sqrt{15-6.76} \\  \\ SO=2.9\text{ cm} \end{gathered}

Length of SO = 2.9 cm

• (3). Area of the base:

To find the area of the triangular base, apply the formula:

A=\frac{1}{2}*BC*AM

Thus, we have:

\begin{gathered} A=\frac{1}{2}*6^*5.2 \\  \\ A=15.6\text{ cm}^2 \end{gathered}

The area of the base is 15.6 square cm.

• (4). Area of the side surface.

Apply the formula:

SA=\frac{1}{2}*p*h

Where:

p is the perimeter

h is the slant height, SM = √15 cm

Thus, we have:

\begin{gathered} A=\frac{1}{2}*(6*3)*\sqrt{15} \\  \\ A=34.86\text{ cm}^2 \end{gathered}

• (5). Total surface area:

To find the total surface area, apply the formula:

TSA=base\text{ area + area of side surface}

Where:

Area of base = 15.6 cm²

Area of side surface = 34.86 cm²

TSA = 15.6 + 34.86 = 50.46 cm²

The total surface area is 50.46 cm²

• (6). Volume:

To find the volume, apply the formula:

V=\frac{1}{3}*area\text{ of base *height}

Where:

Area of base = 15.6 cm²

Height, SO = 2.9 cm

Thus, we have:

\begin{gathered} V=\frac{1}{3}*15.6*2.9 \\  \\ V=15.08\text{ cm}^3 \end{gathered}

The volume is 15.08 cm³.

ANSWER:

• 1.) 5.2 cm

,

• 2.) 2.9 cm

,

• 3.) 15.6 cm²

,

• 4.) 34.86 cm²

,

• (5). 50.46 cm²

,

• 6). 15.08 cm³.

7 0
10 months ago
Soulutions for 20-4u
Mnenie [13.5K]

The question seems incomplete

3 0
3 years ago
Read 2 more answers
Please help and explain ( Brainliest for answer!)
Novosadov [1.4K]

Answer:

AD = 3

Step-by-step explanation:

Pythagoras theorem formula: a² + b² = c² (c being the hypotenuse, the longest side of the triangle).

Using this formula, you can easily say that c²-b²=a². c=5, b=4, making the equation 5² - 4² = a ².

Expanding the formula, you'll get 25 - 16 = a².

25 - 16 = 9.

This means that 9 = a².

To find a, you need to root 9. Using a calculator, you'll know that this number is 3, meaning that AD = 3.

7 0
3 years ago
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