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anastassius [24]
3 years ago
14

Ummm i know both of these are easy but i can't remember them please help

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
4 0
It is 4 because 3 times 4 equals 12
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Need help with 34,35,36,37
nirvana33 [79]
34. x - 3 = 8x + 4
      -3 - 4 = 8x - x
      -7 = 7x
      -7/7 = x
      -1 = x

y = x - 3
y = -1 - 3
y = -4

solution is (-1,-4)
===================
35. -6 = -x - 2y
      x = -2y + 6

2 + 5x = -2y
2 + 5(-2y + 6) = -2y
2 - 10y + 30 = -2y
32 = -2y + 10y
32 = 8y
32/8 = y
4 = y

2 + 5x = -2y
2 + 5x = -2(4)
2 + 5x = -8
5x = -8 - 2
5x = -10
x = -10/5
x = -2

solution is (-2,4)
==================
36. 4x + 6y = 2000
       x + y = 410
==================
37. 4x + 6y = 2000
       x + y = 410......multiply by -6
----------------------
4x + 6y = 2000
-6x - 6y = - 2460 (result of multiplying by -6)
--------------------add
-2x = - 460
x = -460/-2
x = 230 <=== tickets in advance
 

3 0
2 years ago
I’ll give extra points
ollegr [7]

Answer:

the 2nd one

Step-by-step explanation:

5 0
2 years ago
I need help with this question ASAP!!!
alex41 [277]
I’m not sure sorry also it past due
4 0
3 years ago
   2. By selling an article for ₹1636.25, a dealer gains ₹96.25. Find his gain percentage.  ​
madreJ [45]

Answer is..

5.88%

(96.25/1636.25)%

= 5.88%

4 0
2 years ago
There are 1,657 souvenir paperweights that need to be packed in boxes. Each box will hold 17
blondinia [14]

Answer:

Therefore we can say that 98 boxes will be needed to hold all the paperweights.

Step-by-step explanation:

i) there are 1657 souvenir paperweights that need to be packed in boxes.

ii) each box will hold 17 paperweights

iii) therefore the number of boxes that will be needed are

   = \dfrac{total\hspace{0.15cm} number\hspace{0.15cm} souvenir\hspace{0.15cm} paperweights}{number\hspace{0.15cm} of\hspace{0.15cm} paperweights\hspace{0.15cm} per\hspace{0.15cm} box}  = \dfrac{1657}{17} = 97.471

iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.

4 0
3 years ago
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