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Sholpan [36]
3 years ago
11

How many solutions does this system have?

Mathematics
1 answer:
zhenek [66]3 years ago
5 0

Answer:

A. None

General Formulas and Concepts:

<u>Algebra I</u>

  • Perpendicular Lines/Intersecting Lines have 1 solution.
  • 2 identical Lines have infinitely many solutions.
  • Parallel Lines have no solution.

Step-by-step explanation:

According to the graph, we see that we have 2 parallel lines. Therefore, there will be no solution.

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NO LINKS!!!!
DedPeter [7]

9514 1404 393

Answer:

  3. vertical stretch by a factor of 2; shift right 1 and down 1

  4. shift left 4 and up 4 (no stretch or shrink)

Step-by-step explanation:

The vertex form equation is ...

  y = a(x -h)^2 +k

It represents a vertical stretch of the parent function by a factor of 'a', a right shift of 'h', and an upward shift of 'k'.

Compare the the given equations to the above form to see the transformations.

__

3. (a, h, k) = (2, 1, -1)   ⇒   vertical stretch by a factor of 2; shift right 1, down 1

4. (a, h, k) = (1, -4, 4)   ⇒   no vertical stretch; shift left 4, up 4

6 0
3 years ago
It is a well-known fact that 50% of the general population are rascals (P(R) = 0.5) and 50% of the general population are not ra
aleksley [76]

Answer:

The answer is D. 0.75

Step-by-step explanation:

Let call R the event that a person is rascal, RC a person is not rascal, TH a person use top hat and NTH a person don’t use top hat.  

From the information on the question we have 4 options with their respective probability:

1. A person could be rascal and use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and use a top hat (0.9), then:

P(R y TH)=0.5*0.9=0.45

2. A person could be rascal and don’t use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and not use a top hat (0.9), then:

P(R y NTH)=0.5*0.1=0.05

3. A person could be not rascal and use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and use a top hat (0.3), then:

P(RC y TH)=0.5*0.3=0.15

4. A person could be not rascal and not use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and not use a top hat (0.7), then:

P(RC y NTH)=0.5*0.7=0.35

Then the probability that a person is a rascal given that he is wearing a top hat could be written and calculate as:

P(R/TH)=\frac{P(R y TH)}{P(TH)}

For calculate P(TH) we need to sum all the option in which TH is involve so:

P(TH) = P(R y TH)+ P(RC y TH)

P(TH)=0.45+0.15=0.6

Replacing values on the first equation we get:

P(R/TH)=\frac{0.45}{0.6} =0.75

So, the probability that a person is a rascal given that he is wearing a top hat is 0.75

5 0
3 years ago
Based on the tables, at what point do the lines y = 3x - 2 and y = -5x - 10 intersect?
Pepsi [2]
Intersect at where x=x and y=y
see where they have the same x and y values
that is at x=-1 and y=-5
intersect at (-1,-5)
8 0
3 years ago
What is 10 times 2.50?
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Twenty five dollars answeris

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3 years ago
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