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gladu [14]
2 years ago
12

Lol bro help me :((((((((((((((((((((((((((((((

Mathematics
2 answers:
Nady [450]2 years ago
8 0

I thank

x=-y/3+z

it help you

Feliz [49]2 years ago
7 0

Answer:

The choice four ;

x =  \frac{z - y}{3}

Step-by-step explanation:

3x + y = z \\ 3x = z - y \\ x =  \frac{z - y}{3}

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What is pi ? <br><br><br><br><br><br><br> ps. just trying this -.-
marysya [2.9K]
'Pi' ( π ) is the ratio of the circumference of a circle to its diameter.

The exact value of 'pi' can't be completely written with numbers, so whenever
we use 'pi', we always use an approximation.
7 0
3 years ago
Read 2 more answers
manuel has $15 to spend.on apps and music. Apps cost $2 each and songs cost $1 each. If x represents the number of apps purchase
strojnjashka [21]

Answer:

2x + y = 15

Step-by-step explanation:

Total amount with Manuel = $15

Cost of apps = $2

Cost of song = $1

x = number of apps purchased

y = number of songs purchased

Cost of apps × number of apps purchased + Cost of song × number of songs purchased = Total amount with Manuel

2*x + 1*y = 15

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The linear equation that represents the combination of apps and songs manuel can purchase is 2x + y = 15

6 0
3 years ago
BRAINLIEST to correct answer!!
Len [333]

They are equally spaced so all the circles share the same center point.

4 0
2 years ago
Read 2 more answers
What is x? Please help fast
Firdavs [7]

Answer:

x = 47°

Step-by-step explanation:

m∠DPB + ∠BPC = 180° (Definition of a straight line)

Plug in the corresponding numbers and variables to the corresponding places:

x + 133 = 180

Isolate the variable, x. Subtract 133 from both sides:

x + 133 (-133) = 180 (-133)

x = 180 - 133

x = 47

47° is your answer.

~

3 0
3 years ago
Read 2 more answers
2x^2y^3z^2 · 4xy^4x^2<br><br> Multiply and simplify
Advocard [28]

Take out the constants

(2 × 4)x^2xx^2y^3y^4z^2

Simplify 2 × 4 to 8

8x^2xx^2y^3y^4z^2

Use the Product Rule: x^ax^b = x^a + b

8x^2 + 1 + 2y^3 + 4z^2

Simplify 2 + 1 + 2 to 5

8x^5y^3 + 4z^2

Simplify 3 + 4 to 7

<u>8x^5y^7z^2</u>

6 0
3 years ago
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