The inequalities are matched with their correct graph respectively as follows:
- D ⇒ {(x, y): y > x²}.
- G ⇒ {(x, y): y ≥ x²+ 3
- C ⇒ {(x, y): y ≤ 3x² + 2}
- A ⇒ {(x, y): y ≥ 2x² - 5x + 1}
- J ⇒ x²- 3x ≥ 0
- H ⇒ x² - 3x + 2 ≤ 0
- B ⇒ {(x, y): y ≤ 1 - x²}
- B ⇒ {(x, y): y ≥ -1}
<h3>What is a graph?</h3>
A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.
<h3>What is an inequality?</h3>
An inequality can be defined as a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following arguments:
- Less than (<).
- Greater than (>).
- Less than or equal to (≤).
- Greater than or equal to (≥).
In Geometry, if the leading coefficient of a quadratic equation is greater than (>) zero, the parabolic curve would open upward while the parabolic curve would open downward when the leading coefficient of a quadratic equation is less than (<) zero.
Read more on graph of inequalities here: brainly.com/question/24372553
#SPJ1
Complete Question:
Match the questions with the graphs that are labeled A-H. (keep in mind that some questions might have the same answer)
1. A = {(x, y): y > x^2}
2. B = {(x, y): y ≥ x^2+ 3}
3. C = {(x, y): y ≤ 3x^2 + 2}
4. D = {(x, y): y ≥ 2x^2- 5x + 1}
6. x^2- 3x ≥ 0
7. x^2- 3x + 2 ≤ 0
8. {(x, y): y ≤ 1 - x^2}
9. {(x, y): y ≥ -1}
Step-by-step explanation:
Dbhshsnsbsbusgdhsbshjsshhsns
Anything raised to exponent 0 equals 1
So
So we get
Answer:
You can't have a single answer.
Step-by-step explanation:
An indiviual equation can't be solved if it has 2 variables.
You can, however, graph it.
The line will create all the possible sets of answers for the problem.
Using the cross product property on this proportion gives us the following equation:
20 (2x - 9) = 10 (9)
Use the distributive property and multiply
40x - 180 = 90
Add 180 to both sides
40x = 270
Divide 40 from both sides
x = 270/40
Simplify fraction
x = 27/4
This should be your answer. Let me know if you need any clarifications, thanks!
