Substituting the data points into the model:
f(x)= -x2 + 2x -3
f(-2)=-11
f(0)=-3
f(1)=-2
f(3)=-6
f(5)=-18
So A is the right ans.
Beautiful ! What a great exercise ! I won't even check to verify
that 1:10⁻¹⁹ is an appropriate scale to map the Milky Way onto a
football field. I'll just accept it and go from there.
(4.4 light years) x (10⁻¹⁹) = (2.5848 x 10¹³ miles) x (10⁻¹⁹)
= 2.5848 x 10⁻⁶ mile
= 0.164 inch .
(1,391,400 kilometers) x (10⁻¹⁹) = 1.3914 x 10⁻¹⁰ meter
Research Conclusions:
If the Milky Way shrinks to fit on a football field, then
-- Alpha Centauri is 0.164 inch from us.
-- The sun's diameter is about 1.39 times that of a Hydrogen atom.
Playing with this same fun concept a little more:
-- The Earth is sailing around in its orbit, once a year,
about 0.000015 millimeter from the sun.
-- It takes light almost 27 years to travel 1 inch !
wow !
Answer:
52feet
Step-by-step explanation:
The set up will be a right angle
Let the angle of depression be 30°
The height above the sea level will be the opposite
The distance of the ship from the base is x (adjacent)
Using TOA
Tan theta = opposite/adjacent
Tan 30 = 30/x
x = 30/tan 30
x = 30/0.5774
x = 51.96
x ≈ 52 feet to the nearest foot
Answer:
√7 units, √98 units
Step-by-step explanation:
Pythagorean theorem
a^2+b^2=c^2. So 9+b^2=16. So b^2=7. So b=√7
a^2+b^2=c^2. SO 49+49=c^2. So 98=c^2. So c=√98.
42 because x is equal to its corresponding side
