Answer:
the last choice
Step-by-step explanation:
Add like terms
I'm assuming that you forgot to put the parenthasees at the end
so exg
4x+8x=12x
2x^2+3x^2=5x^2
3x^2+3x^3=3x^2+3x^3
group like tems
6x^3+9x-8+5x-9x^2+7
6x^3-9x^2+14x-1
Just for you beautiful!
Use distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
(11,-4) is (x1,y1) and (-12,-4) is (x2,y2)
Plug in and simplify
d = sqrt((-12 - 11)^2 + (-4 - -4)^2)
d = sqrt((-23)^2 + (0)^2)
d = sqrt(529 + 0)
d = sqrt(529)
d = 23 (positive because length cannot be negative) ;)
1. To solve this problem, you must apply the formula for calculate the area of the trapezoid, which is:
A=(B+b)h/2
A is the area of the trapezoid (A=69.6 in²).
(B+b) is the sum of the bases of the trapezoid.
h is the height of the trapezoid (h=8.7 in).
2. When you clear the sum of the bases (B+b), you have:
A=(B+b)h/2
2A=<span>(B+b)h
</span><span> (B+b)=2A/h
</span> (B+b)=2(69.6 in²)/(8.7 in)
(B+b)=16 in
3. The problem says that <span>the sum of its legs is equal to the sum of its bases, therefore, the perimeter is:
</span>
Sum of the legs=Sum of the bases (B+b)=16 in
Perimeter=16 in+16 in
Perimeter=32 in
Ex: you can do 5-3 by putting a dot on the five and looping back 3 spaces. Hope it helps!
