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SVEN [57.7K]
4 years ago
11

A, B, and C are the vertices of one triangle. D, E, and F are the vertices of another triangle. m∠A = 50, m∠B = 10, m∠E = 40, m∠

F = 30, AB = 6, and DE = 6. Are the two triangles congruent If yes, explain why and tell which segment is congruent to segment A C.
yes, by SAS; DF
yes, by ASA; DF
yes, by AAS; DF.
No, the two triangles are not congruent.
Mathematics
1 answer:
adell [148]4 years ago
3 0
The fourth one seems like its the right one 
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326 rounded to the nearest 100
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4 years ago
5 + 5(x + 4) &lt; 20<br><br>Solve the inequality <br><br>Help plz​
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Answer:

You would solve this as if the inequality sign was an equal sign.

Just make sure when you divide by a negative or multiply by a negative the sign switches, anyways:

5 + 5(x +4) < 20

Distribute the 5 and simplify

5 + 5x + 20 < 20

25 + 5x < 20

Isolate x    (subtract 25 from both sides)

5x < -5

Divide by 5

x < -1

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3 years ago
All contains two distinct points,C and D. Select each statement.
Agata [3.3K]
What’s the statement??
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3 years ago
Suppose a triangle has two sides of length 3 and 4 and that the angle between these two sides is 60°. What is the length of the
lesantik [10]
We can use law of cosines to find the length of the third side.

Law of cosines is:

c^2 = a^2 + b^2 - 2ab*cos(C), where angle C is opposite of side c.

Plug in what we know.

c^2 = 3^2 + 4^2 - 2(3)(4)cos(60)

Simplify:

c^2 = 9 + 16 - 24cos(60)

c^2 = 25 - 24cos(60)

Solve for c by taking the square root of both sides:

c = sqrt(25 - 24cos(60))

c = sqrt(25 - 24(0.5))

c = sqrt(13)

c = 3.606





8 0
3 years ago
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IRISSAK [1]
The answer of the question is
53 ft
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