A quadratic equation given roots is solved by using the relation
![{x}^{2} - (sum \: of \: roots)x + product \: of \: roots](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%20%28sum%20%5C%3A%20of%20%5C%3A%20roots%29x%20%2B%20product%20%5C%3A%20of%20%5C%3A%20roots)
from the question,
sum of the root will be
![\frac{3}{4} + ( - 4) = \frac{3}{4} - 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%2B%20%28%20-%204%29%20%3D%20%20%5Cfrac%7B3%7D%7B4%7D%20%20-%204)
![= \frac{3 - 16}{4}](https://tex.z-dn.net/?f=%20%3D%20%20%20%5Cfrac%7B3%20-%2016%7D%7B4%7D%20)
![= \frac{ - 13}{4}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20-%2013%7D%7B4%7D%20)
and also, product of the roots will
be
![\frac{3}{4} \times ( - 4) = - 3](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%5Ctimes%20%28%20-%204%29%20%3D%20%20-%203)
now substituting the sum of roots and product of roots into the equation
![{x}^{2} - ( - \frac{13}{4} )x - 3](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%20%28%20-%20%20%5Cfrac%7B13%7D%7B4%7D%20%29x%20-%203)
![= {x}^{2} + \frac{13}{4} x - 3](https://tex.z-dn.net/?f=%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%20%5Cfrac%7B13%7D%7B4%7D%20x%20-%203)
as the quadratic equation for the root 3/4 and -4
Do 1/3 x 1/2 to get 1/6, or you could think, 1/3 divided by 2, which would equal 1/3 x 1/2
Answer:
38.5 kg of grass
Step-by-step explanation:
We can solve this problem by using a proportion. (Kg of grass over horses)
Let x = the amount of grass 11 horses will eat in the same period of time.
112/32 = x/11 Cross multiply
1232 = 32x Divide both sides by 32
x = 38.5
I hope this helped and please mark me as brainliest!
Multiply both sides by the reciprocal (-8/7). You would get 40/7 or 5.71428571