Answer:
A)29 and B) 21,
Step-by-step explanation:
First,in the sequence
, the parameter
must to be a integer.
Second, we need to solve the equations by
.

All the option in the problem represent an
Then, we need to prove all number in the options, if the result is a integer number, this option can be part of the sequence.
For A)

For B)

For C)

For D)

Only A) and B) only A and B meet the requirement
Answer:
Step-by-step explanation:
From the given information:
The null and the alternative hypothesis can be well written as:


Given that:
n = 200
x = 135
Alpha ∝ = 0.05 level of significance
Then;
⇒ 
= 200 × 0.6 × (1 -0.6)
= 200 × 0.6 × 0.4
= 48 ≥ 10
The sample proportion 

= 0.675
The test statistics 


Z = 2.165
The P-value = P(Z > 2.165)
= 1 - P(Z < 2.165)
From the z tables
= 1 - 0.9848
= 0.0152
Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).
Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6
Answer:
Csc(pi)
Cot(pi)
Csc(0)
Sec(90)
Step-by-step explanation:
Answer:
4120
Step-by-step explanation:
Answer:
you just shoed the answers
Step-by-step explanation: