Answer:
90°
i went on a whim and guessed it was a right angle, sorry I can't provide reasoning! but it is for sure 90°
Step-by-step explanation:
14x + 5 + 90 = 165
14x + 95 = 165
-95 -95
14x = 70
/14 /14
x = 5
14(5) + 5 +90 = 165
70 + 95 = 165
165 = 165
The required plane Π contains the line
L: (-1,1,2)+t(7,6,2)
means that Π is perpendicular to the direction vector of the line L, namely
vl=<7,6,2>
It is also required that Π be perpendicular to the plane
Π 1 : 5y-7z+8=0
means that Π is also perpendicular to the normal vector of the given plane, vp=<0,5,-7>.
Thus the normal vector of the required plane, Π can be obtained by the cross product of vl and vp, or vl x vp:
i j k
7 6 2
0 5 -7
=<-42-10, 0+49, 35-0>
=<-52, 49, 35>
which is the normal vector of Π
Since Π has to contain the line, it must pass through the point (-1,1,2), so the equation of the plane is
Π : -52(x-(-1))+49(y-1)+35(z-2)=0
=>
Π : -52x+49y+35z = 171
Check that normal vector of plane is orthogonal to line direction vector
<-52,49,35>.<7,6,2>
=-364+294+70
=0 ok
Answer:
Sure
Step-by-step explanation:
Answer:
Aw thanks so much!
I hope you have the best day and a good nights rest.
