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Annette [7]
3 years ago
13

Help. I forgot how to do this please

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
5 0

Answer:

  176 in³

Step-by-step explanation:

Area is a 2-dimensional measure, so the scale factor for area of similar figures is the 2nd power of the linear scale factor. That is, the ratio of linear dimensions of the two figures is ...

  smaller/larger = √(228/1425) = √(4/25) = 2/5 . . . . linear scale factor

Volume is a 3-dimensional measure, so the scale factor for volume of similar figures is the 3rd power of the linear scale factor. That is, the ratio of volumes of the two figures is ...

  smaller/larger = (2/5)^3 = 8/125 . . . . . . . . volume scale factor

Multiplying this by the larger volume gives us the smaller volume:

  (8/125)·(2750 in³) = 176 in³

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What is the quotient a-3/7÷3-a/21
Airida [17]
I wish you were using parentheses here.  I must assume (without knowing for sure) that y ou mean

a - 3/7
----------
3 - a/21

The LCD here is 21, since 7 divides into 21 without a remainder. 

Thus, multiply numerator and denominator by 21:


21a - 9
-----------
63 - a

You could leave this result as is, or you could factor out 3:
    
     7a-3
3 ---------
    63-a
3 0
3 years ago
Read 2 more answers
Find the 12th term of an AP of the form 7, 12, 17, 22
Nostrana [21]

Answer:

27

Step-by-step explanation:

The rule will be

Ni=(i-1)*5+2

  • i=1 → N=(1–1)*5+2=0*5+2=0+2=2
  • i=2 → N=(2–1)*5+2=1*5+2=5+2=7
  • i=3 → N=(3–1)*5+2=2*5+2=10+2=12
  • i=4 → N=(4–1)*5+2=3*5+2=15+2=17
  • i=5 → N=(5–1)*5+2=4*5+2=20+2=22
  • i=6 → N=(6–1)*5+2=5*5+2=25+2=27

________________

Learn more about arithmetic sequences:

  • brainly.com/question/6561461
  • brainly.com/question/503167

#SPJ2

6 0
2 years ago
Suppose x represents an objects weight on Earth. Write two expressions: one that you can use to find the objects weight on Mars
tatyana61 [14]
The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
4 0
3 years ago
PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM
Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

c^{2} =a^{2} +b^{2}

c = \sqrt{a^{2} +b^{2} }

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = \sqrt{40^{2} + 9^{2} }

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = \sqrt{12^{2} + 13^{2} }

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

35^{2} = 20^{2} + b^{2}

1225 = 400 + b^{2}

b^{2} = 1225 - 400

b^{2} = 825

\sqrt{b^{2} } = \sqrt{825}

b = 5 \sqrt{33}

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

c^{2} =a^{2} +b^{2}

37^{2} = 20^{2} + b^{2}

1369 = 400 + b^{2}

b^{2} = 1369 - 400

b^{2} = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0
3 years ago
I bet I will mark you as a brainiest if u get this right
alexgriva [62]

Answer:

6%

Step-by-step explanation:

This is an honest guess just because you are not given the content of 2 out of the 3 bags. When starting at 100 percent of the makeup of the porridge you can then divide that by 3 to get the content of 1 bag. You will get around 33 then you find what 20% of 33 is which is closest to either 6 percent.

7 0
3 years ago
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