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sineoko [7]
4 years ago
13

Can you help me with my math problems

Mathematics
1 answer:
Gemiola [76]4 years ago
5 0
The dependent variable is the one on the Y (vertical) axis
The independent variable is the one on the X (horizontal) axis

OH OH OH
i just remembered, in 6th or 7th grade, my science teacher gave us a way to remember which is which.

DRY MIX
DRY - Dependent (Responding) is on the Y axis
MIX - Manipulated (Independent) is on the X axis

Hope this helps!

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Solve for the variable 2x -28 =16
BigorU [14]

Answer:

x=22

Step-by-step explanation:

5 0
3 years ago
Solve the following expressions (plz explain)
Mars2501 [29]
9 to the 3rd power is 729 And 2 to the 5th power is 32. You multiple 9, 3 times. 9 times 9 times 9 and you multiply 2, five times. 2 times 2 times 2 times 2 times 2
7 0
3 years ago
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A string of decorative lights is 28 feet long. The first light on the string is 16 inches from the plug. If the lights on the st
lilavasa [31]
Well if there is 28 feet, that would be (12x28) 336 inches,  and 16 inches between the plug and the first light, there would be only 320 inches left for lights. therefore, if there are 4 inches between each light, we divide 320 by 4.  the answer we get is 80. there are 80 lights.
7 0
4 years ago
A boy makes a cuboid of plasticine of sides 5cm, 2cm, 5cm. How manny such cuboids will he need to form a cube?
ruslelena [56]

Answer:

Step-by-step explanation:

L.C.M. of 5,2=10

so it should be  of dimensions 10×10×10

it should have 5 cuboids in first row.

then it will make a cuboid 5×10×5

5 cuboids in the second row on top of first row .

Then it will make 5×10×10 cuboid

To make 10×10×10

double the cuboids  to make the length=10 and height=10..

so in all 20 cuboids are needed.

2 rows of 5 cuboids on the floor and 2 rows of 5 cuboids on the top.

in all 10 cuboids of  dimensions 5×2×5

so 9 more cuboids are needed to make a c

3 0
3 years ago
The function f(t)= 5 tan 2 t, does not have an amplitude and has a period of π.
trasher [3.6K]

ANSWER

False

EXPLANATION

The tangent function has no amplitude because it is not bounded.

The given tangent function is

f(t) = 5 \tan(2t)

This is of the form

f(t)=a tan(bt)

The period is given by

T =  \frac{\pi}{ |b| }

T =  \frac{\pi}{ |2| }  =  \frac{\pi}{2}

The first statement is true but the second is false.

Hence the whole statement is false.

8 0
3 years ago
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