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sineoko [7]
4 years ago
13

Can you help me with my math problems

Mathematics
1 answer:
Gemiola [76]4 years ago
5 0
The dependent variable is the one on the Y (vertical) axis
The independent variable is the one on the X (horizontal) axis

OH OH OH
i just remembered, in 6th or 7th grade, my science teacher gave us a way to remember which is which.

DRY MIX
DRY - Dependent (Responding) is on the Y axis
MIX - Manipulated (Independent) is on the X axis

Hope this helps!

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What is the slope of the line that passes through the points (4, -2) and (24, -17)?
Scorpion4ik [409]
The final slope would be:
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rise over run.

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raw and label a model to find the value of 3··81 4·· 8. Then write and solve an equation that matches the model.
bagirrra123 [75]

For is mathematically given as

<h3>What is the solution of an equation that matches the model.?</h3>

Considering line segments from (0,0,0)origin to (3,0,0) , (3,5,1) and (0,5,1) under the infulence of force

Generally,  the equation for force is mathematically given as

F = z2i + 5xyj + 2y2k

Therefore, Considering u*v

u * v = (u_1j+u_2j+u_3k) * (v_1i+v_2j+v_3k)

u* v = u_1v_1(i * i) + u_1v_2(i * j)+u_1v_3(i * k) + u_2v_1(j * i) + u_2v_2(j * j)+u_2_3(j* k) + u_3v_1(k * i) + u_3v_2(k * j)+u_3v_3(k * k)

Where

i * i = j *j=k * k=0

Hence

u* v = u_1v_2k-u_1v_3j-u_2v_1k+u_2v_3i +u_3v_1j - u_3v_2i

u = (u_1,u_2,u_3) = (0,5,1)\\\\v = (v_1,v_2,v_3) = (-3,0,0)

The normal equation formed

-3y + 15z = 0

z= (1/5)y

Considering the level surface and differential surface area

h(x,y,z) = -y + 5z =0

dS = |grad(h)| dA

In terms of the x and y coordinates of (3,0,0) and (3,5,1) and (0,5,1), we can state that the ranges are 0 to 3 and 5 respectively.

In conclusion,

Read more about

#SPJ1

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