Answer:
genotypic ratio = 2:2
Explanation:
We were being told that when Mendel crossed yellow- seeded and green- seeded pea plants, all the offspring were yellow seeded.
This implies that the Yellow seed trait masked the green seed trait in the F1 generation. The best defination that can be deduced is that;
the yellow-seeded plants are homozygous dominant &
the green-seed pea plants are homozygous recessive
So, let yellow- seeded pea plants= YY
and green- seeded pea plants= gg
i.e YY × gg
| Y | Y
g | Yg | Yg
g | Yg | Yg
F₁ = (Yg, Yg, Yg, Yg,) All the offspring were heterozygous yellow seeded plant.
Now, when he crossed the F₁ heterozygous yellow seeded plant with the green- seeded plants; we will have the following result
i.e Yg × gg
| Y | g
g | Yg | gg
g | Yg | gg
F₂ = (Yg, Yg, gg, gg)
The F₂ generation would have genotypes of (Yg, and gg) and a genotypic ratio of 2:2
Answer:
A. Hunting and killing the snakes on the farm
Explanation:
Snakes are naturally born predators and rodents such as rats and mice serve as their preys. Hence, their presence on the farm will limit the population of rodents in such farm.
<em>Therefore, hunting and killing all the snakes on the farm will allow rodent population to flourish, leading to a spike in their population.</em>
The correct option is A.
Answer:
Restriction enzymes are DNA-cutting enzymes. Each enzyme recognizes one or a few target sequences and cuts DNA at or near those sequences.
Many restriction enzymes make staggered cuts, producing ends with single-stranded DNA overhangs. However, some produce blunt ends.
DNA ligase is a DNA-joining enzyme. If two pieces of DNA have matching ends, ligase can link them to form a single, unbroken molecule of DNA.
In DNA cloning, restriction enzymes and DNA ligase are used to insert genes and other pieces of DNA into plasmids.
Explanation:
Hello.
The control group is the group that gets no specal treatment.
If your askiing if that statment is true it is.
Have a nice day
Answer:
C it has pairs of matching chromosomes
