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PIT_PIT [208]
4 years ago
10

What is 5/8 times 28 i need help

Mathematics
2 answers:
Sergio [31]4 years ago
8 0
Its 5 because you have to change 28 into a fraction by putting a one under like so 28/1
Ghella [55]4 years ago
7 0
Dear Unab,
your answer should be  17 1/2.
Hope this helps! :)
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Answer:

60! hope this helps!

Step-by-step explanation:

4 0
3 years ago
Simplify each expression. <br>(4 - 2i) - (-3 + i) ​
PtichkaEL [24]

Answer:

2i - (-3 + i)

Step-by-step explanation:

I think this is it. Sorry if it's wrong

7 0
3 years ago
Read 2 more answers
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
Two runners start at the same point;Jayne and Jared.
Tomtit [17]

Answer:

160

Step-by-step explanation:

  1. 8
  2. 16
  3. 24
  4. 32
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  8. 64
  9. 72
  10. 80
  11. 88
  12. 96
  13. 104
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  15. 120
  16. 128
  17. 136
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6 0
3 years ago
Does anyone know the answers to I-ready ( Math Lvl F: Understanding Algerbretic Expressions)
sergij07 [2.7K]

Answer:

B 10x+5

Step-by-step explanation:

:)

5 0
3 years ago
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