Answer:
8 cans
Step-by-step explanation:
Heyyyoooooooooo I got youuuuuu giveeee meeee a second pleaseeeeeee
<h2><u>COMBINED OPERATIONS</u></h2><h3>Exercise</h3>
First, let's solve the subtraction (in parentheses):


Now, let's solve the multiplication. Remember: in multiplication, two negative numbers will give a positive number:


Finally, let's solve the division:

<h3><u>Answer</u>: 16</h3>
There isnt one its has to be consistent but honestly idk
F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3
2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10
3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2