All categories

3 years ago

How many lines of symmetry does the figure have? Which letter has rotational symmetry ?

Mathematics

2 answers:

Hunter-Best [27]3 years ago

6 0

Problem 2

The figure has one line of symmetry.

This line is vertical and passes through the direct center. Imagine folding one side to have it land perfectly on the other side.

================================

Problem 3

The letter Z has rotational symmetry.

If we were to look at the letter, close our eyes, and then rotate it 180 degrees (or have a friend do so), we wouldn't see any difference if we opened our eyes again. The "before" and "after" images being identical is what gives it rotational symmetry. Put another way, rotating the letter 180 degrees has it line up with itself.

erica [24]3 years ago

3 0

Answer:

42, B. 1

Step-by-step explanation:

You might be interested in

How can you find 50% of any numbers

blagie [28]

Answer:

Divide it by two

Step-by-step explanation:

Divide it by two

4 0

3 years ago

Read 2 more answers

1. Is the relation a function and why or why not? {(1, 2), (2, 3), (1, 6), (4,3)}

weqwewe [10]

Answer:

Its not a function, D

Step-by-step explanation:

its not a function because the x value, 1, repeats. input is x and output is y, so the input of 1 has more than one output.

7 0

3 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

Does anyone know how tj do this (trig)

Crank

Answer:

x = 5

Step-by-step explanation:

NOTE: THE 2 SIDES ARE THE SAME LENGTH

THEY HAVE TO BE SMALLER THEN 10

So 10/2 = 5

x = 5

Please mark as brainliest

Have a great day, be safe and healthy

Thank u

8 0

3 years ago

Find the value(s) of h for which the vectors are linearly dependent. Justify your answer. [Start 3 By 1 Matrix 1st Row 1st Colu

RideAnS [48]

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

4 0

3 years ago