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3 years ago

Determine which of the following graphs does not represent a function. (Help me ASAP)

Mathematics

1 answer:

dedylja [7]3 years ago

7 0

Answer:

Step-by-step explanation:

one way to determine whether or not something is a function is to use the vertical line test

You can draw vertical lines all along the figure and if the same vertical line touches 2 parts of the graph we know this is not a function due to there being 2 outputs for the same x value

d is a vertical line and therefore will not pass this test

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Find x when g(x)=4<br> x=

aniked [119]

Answer:

Nonsensical

Step-by-step explanation:

g(x) essentially means y, so this problem is asking for a unknown variable.

-Mr. Willams

7 0

2 years ago

What’s the answer please help me no links at all if you do I will report

ANEK [815]

Answer: 78

Step-by-step explanation:

7 0

2 years ago

The product of 5 and 2 less than triple a number equals the product of 7 and 8 more than twice the number. What is the number?

Oksi-84 [34.3K]

Answer:Hi,

Let the number be x

Twice the number is 2x

Five less than twice the number is 2x-5, which is given as 9

Therefore, 2x-5 = 9

or, 2x = 9+5

or, 2x = 14

or x=7

Thus the number is 7.

Cheers

Step-by-step explanation:

5 0

2 years ago

A child walks due east on the deck of a ship at 3 miles perhour.

VladimirAG [237]

Answer:

16.28 mph ; 79.38°

Step-by-step explanation:

Given the following :

Speed of child due east = 3mph

Speed of ship due North = 16mph

Relative speed of th child is obtained by using Pythagoras rule to find the hypotenus

Relative Speed = Sqrt(3² + 16²)

Relative Speed = sqrt(9 + 256)

= sqrt(265)

= 16.2788 mph

= 16.28 mph

From trigonometry ;

Tanθ = opposite / Adjacent

Tanθ = (16 / 3)

Tanθ = 5.333

θ = tan^-1(5.333)

θ = 79.379°

θ = 79.38°

6 0

3 years ago

A 46 gram sample of a substance that is used to sterilize surgical instruments has a k-value of 0.1374. Find the substance's hal

mars1129 [50]

Answer:

$t=5.0days$

Step-by-step explanation:

Using the formula for the exponential decay that is $N=N_{0}e^{-kt}$ , we have N= $\frac{1}{2}{\times}46=23$ , $N_{0}=46$ and k=0.1374.

Thus, $N=N_{0}e^{-kt}$ becomes

$23=46{\times}e^{-0.1374t}$

$\frac{23}{46}=e^{-0.1374t}$

$\frac{1}{2}=e^{-0.1374t}$

Taking log on both sides, we get

$ln(\frac{1}{2})={-0.1374t}$

$t=\frac{ln\frac{1}{2}}{-0.1}$

$t=\frac{-0.6931}{-0.1374}$

$t=5.0days$

4 0

2 years ago