Every 2/3 hour, Harris can sew 1/6 pair of jeans.

1 answer:

5 0

Let r equal to the rate in pairs of jean per hour
J equal tp number of jeans
T equal to time
R = j/t
Since every Every 2/3 hour, Harris can sew 1/6 pair of jeans.
R = ( 1/ 6 jeans) / ( 2/3 hr)
R = ¼ jean per hour is harris’ rate

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This can be written in equation as,

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Nesterboy [21]

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