Write a second linear question to create a system that has no solution for 3x+9y=-8

HELP ME PLEASE AND JUST GIVE ME THE ANSWER NO EXPLANATION

Arisa [49]

The missing end of the line segment $\overline {GH}$ whose midpoint is M(x, y) = (5, 3) and known endpoint is G(x, y) = (1, -5) is the point H(x, y) = (9, 11).

<h3>How to locate the missing end of a line segment</h3>

In this question we know an end and a midpoint of a line segment. The missing end can be found from the following formula:

M(x, y) = G(x, y) + 0.5 · [H(x, y) - G(x, y)]

M(x, y) = 0.5 · G(x, y) + 0.5 · H(x, y)

0.5 · H(x, y) = M(x, y) - 0.5 · G(x, y)

H(x, y) = 2 · M(x, y) - G(x, y) (1)

If we know that M(x, y) = (5, 3) and G(x, y) = (1, -5), then the coordinates of the point H are:

H(x, y) = 2 · (5, 3) - (1, -5)

H(x, y) = (10, 6) - (1, -5)

H(x, y) = (9, 11)

The missing end of the line segment $\overline {GH}$ whose midpoint is M(x, y) = (5, 3) and known endpoint is G(x, y) = (1, -5) is the point H(x, y) = (9, 11).

To learn more on line segments: brainly.com/question/25727583

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3 0

2 years ago

Read 2 more answers

A number is no more than negative 5 or is between 0 and is 6

Sonbull [250]

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8 0

3 years ago

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Given the sequence {-1, 3, 7, 11, ...}, find a25

Lesechka [4]

here,

a1=-1

a2=-1+4 =3

a3= 3+4=7

a4=7+4=11

using the general formula for nth term of an ap

$an = - 1 + (n - 1)d \\ here \: a = - 1 \: and \: d = 4 \\ \\ an = - 1(n - 1)(4) = - 1 + 4 - 4 \\ 4n - 5 \\ \\ hence \: a25 = \\ 4(25) - 5 = 100 - 5 = 95$

Answer= a25 = 95

4 0

3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago

Dg has endpoints D(-1,8) and G(3,4). What are the cooridantes of its midpoint.

Fed [463]

To find the midpoint, we first add the points of the x values (-1 and 3), which is 2. Divide that by 2 to get 1 as our x value. Repeat for the y values to get (8+4)/2=6 and our midpoint is (1, 6)

7 0

3 years ago