Answer:
Dont count me if I'm wrong but if you divide 225 by 30 you get 7.5
So your answer should be 7.5
here is the solution to the question
Answer:

Step-by-step explanation:
We need to integrate the given expression. Let I be the answer .
- Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
- Now , Rewrite using du and u .

SO YOU HAVE X(-14X+9). ALL YOU DO IS THE DISTRIBUTION PROPERY OR MULIPLE BY X
SO WE GET -14X^2+9X.
X(-14X+9)= -14X(*)X+9(*)X= -14X^2+9X
HOPE THIS HELPS
I think it A... But if it not sorry I didn’t help... hope this is the answer I am sure it is...