A person has 5 tickets for a concert and she wants to invite 4 of her 8 best friends. How many choices does she have, if two of

Question

3 years ago

8

her friends do not get along and cannot be both invited?

1 answer:

kirill [66] · Answer 1 · 2022-06-29T14:17:55+03:00

Answer:

55

Step-by-step explanation:

Combinations formula is used to make choice of 'R' out of 'N' options =

N(C)R = N ! / [ R ! . (N-R)! ]

Total choices to choose 4 out of 8 friends = 8C4

= 8! / (4! 4!)

= 70

Choices for calling them 2 together = 2C2 x 6C2

= 1 x [ 6! / (2! 4!)]

= 15

So : Number of choices that the 2 friends are not called together = Total choices - choices they are called together

= 70 - 15 = 55