This is a difference of perfect squares which is of the form:
(a^2-b^2)
And which always factors to:
(a-b)(a+b)
In this case:
(5x-8)(5x+8)
Answer:
A. m^2+7m+10=0
Step-by-step explanation:
This is a problem in pattern matching, and in substituting a variable for a pattern.
(x^2+3)^2 +7x^2 +21 = -10 . . . . . . given
(x^2 +3)^2 +7(x^2 +3) = -10 . . . . . factor the last two terms
m^2 +7m = -10 . . . . . . . . . . . . subsitute m for x^2 +3
m^2 +7m +10 = 0 . . . . . . . . add 10 to both sides; matches A
Answer:
r5 tj rhe 62hs fgus us reallh bard lil
Answer:
R = 118
Step-by-step explanation:
Given
Represent the polynomial with P and the divisor with D


Required
Determine the remainder
We start by equating the divisor to 0
i.e.



Substitute 2 for x in the polynomial.
This gives remainder (R)




<em>Hence, the remainder is 118</em>