The probability that both of the students are on Team D is about 5.56%
There are 4 teams, so the first person has a 1/4 chance of being on Team D.
However, for the second person, there are only 6 spots left out of 27 to be on Team D.
To find the combined probability, we need to multiply the two fractions.
1/4 times 6/27 = 1/18 or about 5.56%
(3+3+3+3=12) (3x4=12)
(-3) +(-3)+ (-3)+ (-3)= (-12) (-3x4=-12)
Answer
<span>m∠WXY + m∠YXZ = 180°</span>
The scenario can be described using a piecewise function like:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
<h3>
When the value exists but the limit does not?</h3>
Remember that the limit only exists if the limit from left and the limit from the right give the same value.
Then, we can just define a piecewise function of the form:
f(x) = 1/x if x < c.
f(x) = x if x = c
f(x) = 1/(x + 73) if x > c.
Clearly, this is not a continuous function.
Notice that:
So the limits from left and right are different, then:
Does not exist.
If you want to learn more about limits:
brainly.com/question/5313449
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Answer:
Step-by-step explanation:
Use synthetic division:
The coefficients of 2x^3 - 1 are {2, 0, 0, -1}. Setting up synthetic division, we get:
1 / 2 0 0 -1
2 2 2
---------------------------
2 2 2 1
Note that the remainder is 1. The same result would be obtained through long division.
The quotient is 2x^2 + 2x + 2 with a remainder of 1.
