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hjlf
2 years ago
11

What is the answer? -5.5(d-2)=-12.1 what is the value for d

Mathematics
1 answer:
arsen [322]2 years ago
5 0

The answer is I think B

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. A grocery store clerk put only packages of flour tortillas and packages of corn tortillas on a shelf. The ratio of the number
KengaRu [80]

Answer: It should be 18...(Multiple of 9)

Step-by-step explanation:

3 0
2 years ago
Use the method from the Example to approximate the solution to the equations below to two decimal places.
STALIN [3.7K]

Answer:

x = 3.85

Step-by-step explanation:

Given equation:

6ˣ = 1,000

now,

on taking log both sides, we get

⇒ log(6ˣ) = log(1,000)

or

⇒ log(6ˣ) = log(10³)

now we know the property of log function that

log(aᵇ) = b × log(a)

thus, applying the above property, we get

⇒ x × log(6) = 3log(10)

or

⇒ x × log(2×3) = 3log(10)

now,

we have another property of log function as":

log(A) = log(A) + log(B)

therefore,

x × [log(2) + log(3)] = 3log(10)

also,

log(10) = 1

log(2) = 0.3010

log(3) = 0.4771

Thus,

⇒ x × [0.3010 + 0.4771 ] = 3 × 1

or

⇒ x × 0.7781 = 3

or

⇒ x = 3.85

3 0
2 years ago
If the sum of 9 and a half a number equals 35 translation?
Ratling [72]

9+1/2x=35

x=52

hope this helps

4 0
2 years ago
-9x + 12x + 10 simplifies to
Free_Kalibri [48]

Answer:

\boxed{\sf 3x + 10}

Step-by-step explanation:

Simplify the following:

⇒-9 x + 12 x + 10

Grouping like terms:

⇒(12 x - 9 x) + 10

12 x - 9 x = 3 x:

⇒3 x + 10

5 0
3 years ago
Read 2 more answers
the straight line L, has equation y=3x-4 The straight line 1, in perpendicular to L, and passes through the point (9.5) Find an
kari74 [83]

Given:

The equation of given line is

y=3x-4

A line is perpendicular to the given line and passes through the point (9,5).

To find:

The equation of the perpendicular line.

Solution:

We have,

y=3x-4

On comparing this equation with slope intercept form y=mx+b, we get

m=3

It means, the slope of the given line is 3.

The product of slopes of two perpendicular lines is -1.

m\times m_1=-1

3\times m_1=-1

m_1=-\dfrac{1}{3}

Point slope form of a line is

y-y_1=m(x-x_1)

Where, m is the slope.

The slope of perpendicular line is -\dfrac{1}{3} and it passes through the point (9,5). So the equation of the line is

y-5=-\dfrac{1}{3}(x-9)

y-5=-\dfrac{1}{3}(x)-\dfrac{1}{3}(-9)

y-5=-\dfrac{1}{3}x+3

Adding 5 on both sides, we get

y-5+5=-\dfrac{1}{3}x+3+5

y=-\dfrac{1}{3}x+8

Therefore, the equation of required line is y=-\dfrac{1}{3}x+8.

5 0
2 years ago
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