Answer:
4224
Step-by-step explanation:
Here, we want to calculate the sum of the first 44 digits
Term a which is first digit is 10
common difference which is difference of terms = 14-10 = 18-14 = 4
Now the nth term of an arithmetic sequence is
a + (n-1)d
44th term means n = 44
10 + (44-1)4
10 + 43(4)
10 + 172 = 182
To find the sum, we use the formula
Sn = n/2[a + L]
where a is the first term and L is the 44th term
Sn = 44/2 (10 + 182)
Sn = 22(192)
Sn = 4,224
Answer:
14pqr+35pqr = pqr×(14+35)
Answer:
the answer would be 72
Step-by-step explanation:
Subtract b and then a = (zma) - b
