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krek1111 [17]
3 years ago
14

Please answer it’s fine if you don’t know it.

Mathematics
2 answers:
ANTONII [103]3 years ago
7 0

Answer:

D

Step-by-step explanation:

converting mixed numbers to fractions, our initial equation becomes,

94×71

Applying the fractions formula for multiplication,

=9×74×1

=634

Simplifying 63/4, the answer is

=1534

victus00 [196]3 years ago
3 0
I beleive it is 14 and 1 quarter in.
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Helpp!! The real Tinkerbell is only 5 inches tall in Peter pan. If the scale to create this topiary of Tinkerbell is 1in: 4 feet
Marina86 [1]
20 feet tall I asume
5 0
3 years ago
Read 2 more answers
Angle DEB is 42. State the size of angle ABD
Kay [80]

Answer:

The answer would be 80 ° because 5×( 2 + 13 or x +1 ) is 80

Step-by-step explanation:

ABD is 80°

If DEB is 42 °

∠ ABD = 5(2X+1)

∠ DBC = 3X+6

∠ EBC = Y +135/2

∠ ABD and ∠ DBC are linear pairs

∴ ∠ ABD +∠ DBC = 180

∴ 5(2X+1) + 3X+6 =180

solve for x

∴ x = 13

∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135

 ∠ DBC = 3x+6  = 3*13+6 = 45

∠ ABD  and ∠ EBC are vertical angles

∴ ∠ ABD = ∠ EBC = 135

∴ y +135/2 = 135

∴ y = 135/2

5 0
3 years ago
Find the value of x in the solution to the system of equations shown.
blagie [28]
Substitute the value of y into the second equation
y = 14x - 6
y = -4x + 48

14x - 6 = -4x + 48
add 6 to both sides
14x = -4x + 54
add 4x to both sides
18x = 54
divide both sides by 18
x = 3

The option is B.) x = 3

Hope this helps!
7 0
3 years ago
Read 2 more answers
7.2 cw homework help
kati45 [8]

Answer:

31. Yes (Y)

WXYZ ~ DABC

S.F.=4


32. Yes (Y)

GHIJ ~ KLMN

S.F.=2/3


33. Missing length: 16


34. Missing length: 30


35. x=7


36. x=10


Step-by-step explanation:

31. The polygons are similar if:

WX/DA=XY/AB

Then:

WX/DA=24/6→WX/DA=4

XY/AB=16/4→XY/AB=4

Like WX/DA=4=XY/AB, the polygons WXYZ and DABC are similar

Scale Factor: S.F.=XY/DA=XY/AB→S.F.=4


32. The polygons are similar if:

GH/KL=HI/LM=IJ/MN=GJ/KN

Then:

GH/KL=6/9=(6/3)/(9/3)→GH/KL=2/3

HI/LM=4/6=(4/2)/(6/2)→HI/LM=2/3

IJ/MN=4/6=(4/2)/(6/2)→IJ/MN=2/3

GJ/KN=4/6=(4/2)/(6/2)→GJ/KN=2/3

Like GH/KL=HI/LM=IJ/MN=GJ/KN=4, the polygons GHIJ and KLMN are similar

Scale Factor: S.F.=GH/KL=HI/LM=IJ/MN=GJ/KN→S.F.=2/3


33. If the polygons are similar, their sides must be proportional, then:

x/24=10/15

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 5:

x/24=(10/5)/(15/5)

Dividing:

x/24=2/3

Solving for x: Multiplying both sides of the equation by 24:

24(x/24)=24(2/3)

Multiplying:

x=8(2)

x=16


34. If the polygons are similar, their sides must be proportional, then:

54/63=(54/9)/(63/9)→54/63=6/7

48/56=(48/8)/(56/8)→48/56=6/7

x/35=6/7

Solving for x: Multiplying both sides of the equation by 35:

35(x/35)=35(6/7)

Multiplying:

x=5(6)

x=30


36. (8x-2)/63=42/49

Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 7:

(8x-2)/63=(42/7)/(49/7)

Dividing:

(8x-2)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(8x-2)63=63(6/7)

Multiplying:

8x-2=9(6)

8x-2=54

Adding 2 both sides of the equation:

8x-2+2=54+2

Adding:

8x=56

Dividing both sides of the equation by 8:

8x/8=56/8

Dividing:

x=7


37. (6x-6)/63=42/49=30/35

Simplifying the fractions

(6x-6)/63=(42/7)/(49/7)=(30/5)/(35/5)

Dividing:

(6x-6)/63=6/7

Solving for x: Multiplying both sides of the equation by 63:

63(6x-6)63=63(6/7)

Multiplying:

6x-6=9(6)

6x-6=54

Adding 6 both sides of the equation:

6x-6+6=54+6

Adding:

6x=60

Dividing both sides of the equation by 6:

6x/6=60/6

Dividing:

x=10



8 0
3 years ago
Is<br> sto<br> 40<br> w<br> &amp;<br> 7=<br> 11<br> Z<br> ws
FromTheMoon [43]

Answer:

I don't understand your question but thanks for the points ;) Kinda sucks when someone does it to you, right? Maybe you should stop commenting it on other people's questions so they can get the help they need

8 0
3 years ago
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