1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leokris [45]
3 years ago
7

For nitrogen to be a liquid, its temperature must be within 12.78 °F of –333.22 °F. The equation |x + 333.22 | = 12.78 can be us

ed to find x, which represents the maximum and minimum temperatures at which nitrogen is a liquid.
is the maximum temperature at which nitrogen is a liquid.

is the minimum temperature at which nitrogen is a liquid.
Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

-320.44 & -346

Step-by-step explanation:

i got it right

FinnZ [79.3K]3 years ago
3 0

Answer:

|x + 333.22 = 12.78

Step-by-step explanation:

You might be interested in
Factor by grouping.......
Gekata [30.6K]

Answer:

A. (7n-1) (8n-1)

Step-by-step explanation:

56n^2 -8n-7n+1

56n^2 -8n       -7n+1

Factor out 8n from the first group   and -1 from the second group

8n (7n-1)     -1(7n-1)

Factor out the (7n-1)

(7n-1) (8n-1)

7 0
3 years ago
A Pitcher of fruit punch holds 2 gallons , If 9 people share the entire pitcher equally how much punch does ecah person get
GuDViN [60]
You would do 2 divided by 9 to get that each person would have 2/9 of a gallon or .22 of a gallon. I hope this helps.
5 0
3 years ago
Where should she place the top-left corner of the left-most plaque? 9feet high 11 feet wide 6in of space 2 wide
labwork [276]

Answer:

78

Step-by-step explanation:

8 0
3 years ago
How do i solve 4m^2+3m-1=0 using the quadratic formula
elixir [45]
Quadratic formulat is used when a^2+bx+c=0 x= \frac{-b+/- \sqrt{b^{2}-4ac}   }{2a} 4m^2+3m-1=0 a=4 b=3 c=-1 input x= \frac{-3+/- \sqrt{3^{2}-4(4)(-1)}   }{2(4)} x= \frac{-3+/- \sqrt{9+16}   }{8} x= \frac{-3+/- \sqrt{25}   }{8} x= \frac{-3+/-5  }{8} x= \frac{-8}{8} or \frac{2}{8} x=-1 or 1/4
8 0
4 years ago
I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr
Illusion [34]

Answer:

<h2><u>question 1</u></h2>

n^{2} - 20n -96 = 0

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

<u />x^{2} + 12 x = 48<u />

in the form ax^{2}  +bx +c = 0

= x^{2} +12x - 48

make use of the formula :

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

replace values to make 2 equations :

1.\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1} = 3.17

2.\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1} = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

<u />x^{2} -14x+40=0<u />

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

<u />5b^{2} -20b-18 = 7<u />

in the form ax^{2}  +bx +c = 0

this becomes 5b^{2} -20b-18-7

= 5b^{2} -20b-25

can simplify by 5

= b^{2} -4b-5 =0\\

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0
4 years ago
Read 2 more answers
Other questions:
  • I do not remember how to solve this can you help me
    11·1 answer
  • Can an exponent be negative
    14·2 answers
  • Which expression is equivalent to 3.6 times 3.6 times 3.6 times 3.6?
    6·2 answers
  • What does a tape diagram look like
    13·1 answer
  • The number that occurs twice is the mode?
    5·2 answers
  • The distance from the center of a center of a compact disc to the edge of the disc is 6 centimeters. What is the area of the com
    15·1 answer
  • Given f(x) = 3x - 2, find f(-6).
    12·1 answer
  • What is the equation of this graph?
    5·1 answer
  • Find the value of x.
    14·1 answer
  • Find the midpoint of points A(9,9) and B(2,-1)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!