3 years ago

If (inserted image), then f(2)= A)1/3 B)1 C)7

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

6 0

Given : f(x) = 3x + 1

We get f(2) by substituting x = 2 in the given Function

⇒ f(2) = 3(2) + 1

⇒ f(2) = 6 + 1 = 7

Option C is the Answer

You might be interested in

-10k = 20 <br> Please help I really dont understand.

algol [13]

Answer: Divide each term by − 10 and simplify.

k = −2

6 0

3 years ago

The first equation from the previous system of

icang [17]

Answer:

(x, y) = (-5/3, 22/3)

Step-by-step explanation:

The graph and solution are shown below.

The solution is (-1 2/3, 7 1/3).

6 0

3 years ago

Is anyone gonna answer my dam question -_-

Ostrovityanka [42]

Answer:

What's your question?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

AP Calculus Help Please!

ivanzaharov [21]

4. By the fundamental theorem of calculus,

$\displaystyle\frac{\mathrm dg(x)}{\mathrm dx}=\frac{\mathrm d}{\mathrm dx}\int_{-2}^xf(t)\,\mathrm dt=f(x)$

$g(x)$ is increasing on those intervals where $g'(x)=\dfrac{\mathrm dg(x)}{\mathrm dx}>0$ . So you have

$g'(x)=f(x)=\begin{cases}3&\text{for }-3\le x$

which is clearly positive for $x\in[-3,0)$ , and in the second interval you have

$-x+3>0\implies x$

Together, this means $g'(x)>0$ for all $x\in[-3,3)$ .

5. When $0\le x\le6$ , $f(x)$ reduces to $-x+3$ , so you have

$g(x)=\displaystyle\int_{-2}^xf(t)\,\mathrm dt=\int_{-2}^03\,\mathrm dt+\int_0^x(-t+3)\,\mathrm dt$
$g(x)=6+\left(3t-\dfrac12t^2\right)\bigg|_{t=0}^{t=x}$
$g(x)=6+3x-\dfrac12x^2$

4 0

4 years ago

Which equation represents a line that passes through (–9, –3) and has a slope of –6?

Helen [10]

Answer:

y+3= -6(x+9) is the answer

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers