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3 years ago

If (inserted image), then f(2)= A)1/3 B)1 C)7

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

6 0

Given : f(x) = 3x + 1

We get f(2) by substituting x = 2 in the given Function

⇒ f(2) = 3(2) + 1

⇒ f(2) = 6 + 1 = 7

Option C is the Answer

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What is the product? 2 1/3 × 3 1/4

asambeis [7]

Answer:

7.583333 / 7 7/12

Step-by-step explanation:

2 1/3 × 3 1/4

2 1/3=7/3

3 1/4= 13/4

7/3 * 13/4

=91/12

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4 years ago

on the provided graph, plot the points where the following function crosses the x-axis and the y-axis g(x) = -5^x + 5, what does

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Step-by-step explanation:

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3 years ago

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

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Equation of the midline is y = 1

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Minimum = -3

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1 year ago

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Nimfa-mama [501]

Answer:

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3 years ago

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11111nata11111 [884]

Answer:

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Step-by-step explanation:

d + 0.5 = 0.75

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Hope this helps!!!

4 0

3 years ago

Read 2 more answers