Finance charge is a fee that represents the cost of borrowing or credit.
In this equation, it shows the total amount paid through credit subtracted by the cost of vehicle.
let x be the finance charge
x = $4,100 + 36 months ($251.34/month) - <span>$11,578
</span>x = $4,100 + $9,048.24 - <span>$11,578 </span>
x = ($4,100 + $9,048.24) - $11,578
x = $13,148.24 - $11,578
x = $1,570.24.
The finance charge is $1,570.24
Answer:
it should take her 45 minutes to run 9 laps
Step-by-step explanation:
40/8 = 5
9*5 = 45
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
It could be 2+1 beacuse it says there are twice as many
