Given:
Initial number of bacteria = 3000
With a growth constant (k) of 2.8 per hour.
To find:
The number of hours it will take to be 15,000 bacteria.
Solution:
Let P(t) be the number of bacteria after t number of hours.
The exponential growth model (continuously) is:

Where,
is the initial value, k is the growth constant and t is the number of years.
Putting
in the above formula, we get



Taking ln on both sides, we get

![[\because \ln e^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20e%5Ex%3Dx%5D)



Therefore, the number of bacteria will be 15,000 after 0.575 hours.
Answer:
3rd Option I think-
Step-by-step explanation:
(b - 4z)/7 = a
b - 4z = 7a
b = 7a + 4z
Answer: b = 7a + 4z
Answer:11+2x
Step-by-step explanation:
(10-7-x)+(4+4+3x)
3-x+8+3x
3+8+3x-x
11+2x
Answer:
(- 4, - 10 )
Step-by-step explanation:
y = 5x + 10 → (1)
y = 4x + 6 → (2)
Substitute y = 5x + 10 into (2)
5x + 10 = 4x + 6 ( subtract 4x from both sides )
x + 10 = 6 ( subtract 10 from both sides )
x = - 4
Substitute x = - 4 into either of the 2 equations and evaluate for y
Substituting into (1)
y = 5(- 5) + 10 = - 20 + 10 = - 10
solution is (- 4, - 10 )