R = 2 / (1 + sin <span>θ)
Using the following relations:
R = sqrt (x^2 + y^2)
sin </span>θ = y/R
<span>
R = 2 / (1 + y/R)
R</span>(1 + y/R<span>) = 2
</span><span>R + y = 2
R = 2 - y
sqrt(x^2 + y^2) = 2 - y
Squaring both sides:
x^2 + y^2 = (2 - y)^2
x^2 + y^2 = 4 - 4y + y^2
x^2 + 4y - 4
</span>
The percent markup would be 40%. 10+40%=14
Hope this helps!
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Answer:
J
-66
Step-by-step explanation:
a1 = 2
n = 18
d = - 4
a18 = a1 + (n - 1) * d
a18 = 2 + (18 - 1)*(-4)
a18 = 2 + 17*-4
a18 = 2 - 68
a18 = -66
If xy=0 we assume x and y equal 0
so
the zeros are wehre f(x)=0
0=5(2x-5)(5x+4)
set each to zero
5 is not equal 0 so we don't do that
0=2x-5
5=2x
5/2=x
0=5x+4
-4=5x
-4/5=x
zeroes at x=5/2 and -4/5
