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mel-nik [20]
3 years ago
14

A Celsius thermometer can be used as a physical model of a number line with 0°C representing the freezing point. Select all temp

erature pairs that include numbers that are located on opposite sides of 0°C.
–9°C and 0°C

0°C and 4.4°C

–2°C and –3 1/2°C

–8 1 2 °C and 7°C

2.3°C and –6°C
Mathematics
2 answers:
kipiarov [429]3 years ago
5 0
O*C and 4.4 C step by steo e
iVinArrow [24]3 years ago
3 0

Answer:

<h2>0°C and 4°4C</h2>

Step-by-step explanation:

tell me if i am wrong

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Olenka [21]

3.4 - 2/3 > x

2) simplify 3.4 - 2/3 to 8.2/3

8.2/3 > x

3) Simplify 8.2/3 to 2.733333.

2.733333 > x

switch sides

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How are determinants used to find areas of polygons?
ANTONII [103]
When you arrange the N points in sequence around the polygon (clockwise or counterclockwise), the area is half the magnitude of the sum of the determinants of the points taken pairwise. The N determinants will also include the one involving the last point and the first one.

For example, consider the vertices of a triangle: (1,1), (2,3), (3,-1). Its area can be computed as
  (1/2)*|(1*3-1*2) +(2*-1-3*3) +(3*1-(-1)*1)|
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4 0
3 years ago
Rewrite the expression without parentheses.<br> 13m−​(−9m−4​)
svetoff [14.1K]

Answer:

22m+4

Step-by-step explanation:

Let's break it down:

13m+-1(-9m-4)

13m+(9m+4)

22m+4

7 0
2 years ago
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(a) Let R = {(a,b): a² + 3b &lt;= 12, a, b € z+} be a relation defined on z+)
grin007 [14]

Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

Therefore, R is reflexive

If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

brainly.com/question/1503196

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Can someone please help me with my math question!!
Lena [83]

Answer:

x(12x^2+18x)

Step-by-step explanation:

x(12x^2+18x)=12x^(3)+18x^2

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