Answer:
t = 0.35 seconds
Step-by-step explanation:
We have given the equation:
d=1/2gt²
where,
g = 9.8 m/s²
d = 0.6 m
t = ?
Now put the values in the given formula:
d*2/g = t²
0.6*2/9.8 = t²
1.2/9.8 = t²
0.12245 = t²
Now find the square root of both sides
√t² = √0.12245
t = 0.35 seconds
Part a)
for extraneous solution
<span>
1 ⋅ sqrt(x+2) + 3 = 0</span>
for non extraneous solution
1⋅ sqrt(x+2) + 3 = 6
part b) solve each equation
1⋅sqrt(x+2)+3=0
x+sqrt(x+2)=−3
square both sides
(sqrt(<span>x+2)</span>)^ 2 = (−3)^2
x+2=9
x=9−2
x=7
do you see why its extraneous
Answer: 109.1 degrees
Step-by-step explanation:
To find the angle between the given vectors, we will use the formula below:
Cos(θ) = (U.V)/ |U|.|V|
Where
U = 13i - 8j
V = 2i + 9j
U.V = (2x13) + (-8×9)
U.V = 26 - 72
U.V = - 46
|U| = sqrt ( 13^2 + 8^2)
= sqrt ( 233) = 15.264
|V| = sqrt( 2^2 + 9^2)
= sqrt ( 85 ) = 9.22
Substitute all the value of the parameters into the formula
Cos ø = -46 / (15.3 × 9.2)
Cos ø = - 46 / 140.72
Cos Ø = - 32687
Find the cos inverse of the value
Ø = cos^-1( -32687)
Ø = 109.079 degrees
Therefore, the angle between the given vectors to the nearest tenth of a degree is 109.1 degrees
Ok so we know he used over 700 because he was charged more than 40. Then we take the $8.10 and divide 0.45 into it. This then gives you 18 more minutes. Then add 18 to 700 and you get 718 min.
